How can I remove the file path when using Glob()?

Question

I just want to display the name of my images, without the path (../uploadedImages/)

<?php $images = glob("../uploadedImages/[kK]*.{jpg,png,gif,bmp}",GLOB_BRACE);   
foreach($images as $image) {echo "$image<br>"} ?>

If you chdir(), you can omit the path from the result strings. — mickmackusa
– mickmackusa ♦, Commented Oct 6, 2022 at 10:49

Explosion Pills · Accepted Answer · 2012-10-25 15:26:09Z

24

echo basename($image) . "<br>";

answered Oct 25, 2012 at 15:26

Explosion Pills

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1 Comment

If you just need an array of files: $files = array_map('basename', $files);

gstlouis · Accepted Answer · 2022-12-07 16:53:02Z

1

Although basename is good for a single file, if you need to cut the path for several files that glob gives as array, this way works great.

$contents = str_replace( __DIR__, '', glob( __DIR__ .'/*' ) );

answered Dec 7, 2022 at 16:53

gstlouis

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