Given an array like:
[1, 2, nil, nil, 3, nil, 4, 5, 6, nil, nil, nil]
id like to remove the nil's from the end of the array. Not hard to solve with some ugly loops, but I was hoping there was a Ruby way to do it.
Result: [1, 2, nil, nil, 3, nil, 4, 5, 6]
How about this:
a.pop until a.last
a.pop until a.empty? or a.last
a.pop while a.last.nil? to avoid losing all trailing false's.
Not sure why you would want the nil in between, but I digress!
array = [1, 2, nil, nil, 3, nil, 4, 5, 6, nil, nil, nil]
array.reverse.drop_while {|i| i == nil}.reverse
nils - in my case, I have imported a CSV file which contains column headings - and also some 'white space' columns on the end of each line. The nils in the middle represent 'the user didn't include a value', whereas the trailing ones represent 'the spreadsheet export included dud columns'.foo = [1, 2, nil, nil, 3, nil, 4, 5, 6, nil, nil, nil]
foo.reverse.drop_while(&:nil?).reverse
# [1, 2, nil, nil, 3, nil, 4, 5, 6]
Here's a one-liner for you :)
a = [1, 2, nil, nil, 3, nil, 4, 5, 6, nil, nil, nil]
a[0..a.rindex{|el| !el.nil?}] # => [1, 2, nil, nil, 3, nil, 4, 5, 6]
while(!(a = ar.pop)){}; ar.push a
Still an ugly loop, but maybe less ugly?
