Regex in jQuery: numbers within brackets

Question

Is it possible to get numbers within brackets from string with RegEx? For example, I have selects with content like:

<select class="selectoption">
    <option value="1">no numbers</option>
    <option value="2">3 (+110.0 грн.)</option>
    <option value="3">Blabla (+95.5 грн.)</option>
</select>

I need to get only numbers, when user select option with brackets (110 or 95.5).

Now I have:

$('.selectoption').change(function() {
    if ( $("select option:selected").text().match(/\(.*\)/).length ){}
        alert (
            $("select option:selected").text().match(/\(.*\)/)
        );
    end
});

But it returns (+110.0 грн.) :(

live is deprecated. Just so you'll know.

iMoses
– iMoses

2012-11-09 12:00:14 +00:00
Commented Nov 9, 2012 at 12:00 — iMoses
– iMoses, Commented Nov 9, 2012 at 12:00

Yoshi · Accepted Answer · 2012-11-09 12:09:32Z

4

try:

$('.selectoption').on('change', function () {
  var m = $(this).find(':selected').text().match(/\(.*?([\d.]+).*?\)/);
  console.log(
    m && m[1] || 'n/a'
  ); 
});

http://jsbin.com/ekanog/1/

answered Nov 9, 2012 at 12:09

Yoshi

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1 Comment

Fabrício Matté Over a year ago

+1, I'd post /\(\D*(\d+?(?:\.\d+)?)\D*\)/ as an answer but your regex looks much more cleaner.

Damask · Accepted Answer · 2012-11-09 12:09:29Z

2

Match returns array of char group which you defined in regexp. You can use replace instead match

  $("select option:selected").text().replace(/^(.*)\([^\)\d]*(\d+\.\d+)[^\)\d]*\)$/, '$2')

edited Nov 9, 2012 at 12:09

answered Nov 9, 2012 at 12:04

Damask

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1 Comment

Oleg Pasko Over a year ago

Thanks... I'm not familiar with regex. It returns +110.0 грн., but I don't need + and ` грн.` :)

iMoses · Accepted Answer · 2012-11-09 12:14:04Z

1

Should look something like that:

$('form').on('change', '.selectoption', function() {
    var content = $('option:selected', this).text(),
        matches = content.match(/\([^\d]*(\d+(\.\d*)?)/);
    if (matches.length) {
        alert(matches[1]);
    }
});

form being one of .selectoption parents, change the selector if it is uncorrect.

Incase you don't need delegation you can use:

$('.selectoption').on('change', function() {

As you did on your edit. It's works all the same :)

Example Code

edited Nov 9, 2012 at 12:14

answered Nov 9, 2012 at 12:06

iMoses

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4 Comments

Oleg Pasko Over a year ago

Thanks! But one more thing... (+100 грн.) => 100, but (+99.5 грн.) => 99 (without .5) :-[

iMoses Over a year ago

That's what it does. Look at the code example I've added. (Unless you wanna keep the fraction?)

iMoses Over a year ago

Fixed it to take fractions too.

Oleg Pasko Over a year ago

Works now! Unfortunately, I can't accept more answers, but it's nice variant, thanks!

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