Java Parse Xml Vimeo - extract thumbnail url

Question

I have the following xml file from vimeo: http://vimeo.com/api/v2/video/21331554.xml

I'm trying to extract the thumbnail-medium with the following code:

File fXmlFile = new File("http://vimeo.com/api/v2/video/" + linkId + ".xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
return ((Node) doc.getElementsByTagName("thumbnail_medium")).getNodeValue();

But i get "undefined" as a return

ElderMael · Accepted Answer · 2012-11-15 00:13:10Z

1

You cannot cast a NodeList to Node so this line:

return ((Node) doc.getElementsByTagName("thumbnail_medium")).getNodeValue();

throws a ClassCastException. So you need to get the only item in the NodeList and get its text value with this line:

return doc.getElementsByTagName("thumbnail_medium").item(0).getTextContent();

I tested this with this two methods:

@Test
public void domTestVimeo() throws ParserConfigurationException,
        SAXException, IOException {

    DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
    DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
    Document doc = dBuilder.parse(new ClassPathResource("vimeo.xml")
            .getInputStream());
    doc.getDocumentElement().normalize();

    String val = ((Node) doc.getElementsByTagName("thumbnail_medium"))
            .getNodeValue();

    System.out.println(val);

}

And

@Test
public void yourTest() throws ParserConfigurationException, SAXException,
        IOException {
    // File fXmlFile = new File("http://vimeo.com/api/v2/video/" + 21331554
    // + ".xml");

    InputStream is = new ClassPathResource("vimeo.xml").getInputStream();

    DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
    DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
    Document doc = dBuilder.parse(is);
    doc.getDocumentElement().normalize();
    String val = doc.getElementsByTagName("thumbnail_medium").item(0)
            .getTextContent();

    System.out.println(val);

}

The first throws a ClassCastException and the second prints http://b.vimeocdn.com/ts/137/151/137151977_200.jpg I think that is the value you are looking for.

Also, how did you read from a File object passing a a URL?

answered Nov 15, 2012 at 0:13

ElderMael

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7 Comments

Jerome Ansia Over a year ago

Oh thank you so much for taking the time to give me that detailed answer, I will check this tomorrow. And yes just noticed this as well with the URL and File I didn't know :)

Jerome Ansia Over a year ago

I have some trouble with the ClassPathResource, i don't know from with package this class is from (i also use GAE)

Jerome Ansia Over a year ago

ok i replaced ClassPathRessource by URL() and it's working fine for me now, thanks again ;)

ElderMael Over a year ago

Nice. Can you post the code to load the resource from a URL? It would como handy to know it

Jerome Ansia Over a year ago

Sure i just made the edit to your last answer, thanks again Mael i really appreciate your help and i learned some stuff in the same time ;)

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