PHP call method from class in other class

Question

Code example:

<?php // class_database.php
class database
{
include("class_validation.php"); //this does not work
$val = new validation() //this does not work
    public function login($value)
    {
if($val->validate($value))
{
//do something
}
    }
}

<?php // class_validation.php
class validation
{
    public function validate($value)
    {
if($value > 50) return true;
return false;
    }
}

How do I delegate the class validation in class database? I do not wish to inherit (implement or extends) the class validation -> behavior in validation is not to be changed. I just want to use the methods from validation class. Any OOP solutions? Thanks in advance

Just like your question yesterday, $val will not be in scope in public function login(). You need to define $val inside the function, or as a class property and access via $this->val in the function. — Michael Berkowski
– Michael Berkowski, Commented Nov 16, 2012 at 14:17

Peon · Accepted Answer · 2012-11-16 14:24:01Z

2

You cant use include inside a class like that! Either include it at the beginning of the file ( my suggestion ) or use it one line before $val = new validation(); call.

class_database.php:

<?php
    include("class_validation.php");

    class database
    {
        public function login($value)
        {
            $val = new validation();
            if($val->validate($value))
            {
                //do something
            }
        }
    }
?>

class_validation.php:

<?php
    class validation
    {
        public function validate($value)
        {
            if($value > 50)
                return true;

            return false;
        }
    }
?>

edited Nov 16, 2012 at 14:24

answered Nov 16, 2012 at 14:17

Peon

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2 Comments

Jared Over a year ago

Bonus points for spotting the missing semi colon on $val = new validation()

user1178560 Over a year ago

I tried this before but didn't work. Tried it again and succeeded. Guess I did something wrong before. Thanks!

Kami · Accepted Answer · 2012-11-16 14:16:03Z

0

You need to move the include outside the class. PHP does not allow classes within classes.

Try something like this :

Code example:

<?php 
include("class_validation.php"); // include outside the class declaration
// class_database.php
class database
{

$val = new validation()
    public function login($value)
    {
if($val->validate($value))
{
//do something
}
    }
}

answered Nov 16, 2012 at 14:16

Kami

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Comments

phpisuber01 · Accepted Answer · 2012-11-16 14:16:29Z

0

You can either put the include() outside your class (at the top of your page, class_database.php), or if your using a framework/autoloader you can call it by namespace:

Option 1

<?php
include('class_validation.php');
class database {

}

Option 2

namespace ThisCoolThing;
use \OtherCoolThing\validation;

class database { ... }

answered Nov 16, 2012 at 14:16

phpisuber01

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