I'm looking to shift a register bits n times to the left specified with another register. For example, something like this
shl eax, ebx
The only problem being is that the 2nd operand cannot be a register, it has to be an immediate value. How would I be able to shift a register by a value not known at assemble-time?
In x86 you can specify a shift count in register cl. So shl eax, cl is valid.
mov ecx, ebx
shl eax, cl
Note that you can only use the cl register, not eax or any other register.
Also, shift counts greater than 31 are performed modulo 32. (Not modulo the operand-size, so narrow shifts like shl ax, 20 can shift all the bits out and leave the destination zero. 64-bit shifts mask the count with & 63, though, so shl rax, 32 (or with 32 in cl) is possible. See Intel's manual entry for shl).
The BMI2 instruction set extension supports shifts with the count in any register, and which don't update EFLAGS, so they're more efficient for variable counts:
; if BMI2 is supported
shlx edx, eax, ebx ; edx = eax << (ebx&31)
It's only available on some Haswell+ CPUs, and Excavator / Ryzen CPUs, so you can't use it in fully portable code.
