How to use if/else inside an array

Question

Basically I have a relatively complex piece of code in which has several arrays nested inside each other. I believe that what I'd like to do is not strictly possible:

$selector = true,
 $main_array = array(
  'general' = array(
   'another_array' = array(
    'option1' = array(
     'title' = 'Some Title',
     'type' = 'select',
       if ($selector == true) {
    'option2' = array(
     'title' = 'Some title',
     'type' = 'select',
     } else
    ...

I know that the above is not possible. I know that I could use ternary operator but it didn't work when I tried. I know that there better ways to solve this problem, but as far I can tell, all of them would involve me changing the whole structure (as there are many arrays nested inside each other) which I don't want to do, so my question is, is there a way around that I could use to make this conditional work without me changing the whole thing?

Many thanks

femtoRgon · Accepted Answer · 2012-11-22 00:22:15Z

3

I'm assuming that you are not actually attempting to assign arrays to string literals, so judiciously adding some '>'s

And yes, if I understand what you are looking for, it can be accomplished with a ternary operation, as follows:

$main_array = array(
 'general' => array(
  'another_array' => array(
   'option1' => array(
    'title' => 'Some Title',
    'type' => 'select',
   'option2' => (($selector == true) ?
    array(
     'title' => 'Some title',
     'type' => 'select',
    ) : 'It was false'
 )))));

edited Nov 22, 2012 at 0:22

answered Nov 21, 2012 at 23:57

femtoRgon

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1 Comment

WagnerMatosUK Over a year ago

That's great! I've tried using ternary operation before but I must have ben misusing it as I was getting an error all the time. Now it worked like a charm. Thank you!

user428517 · Accepted Answer · 2012-11-21 23:42:52Z

0

You're right: what you want to do isn't possible the way you want to do it. You'll have to restructure your code. You could push each element into the array individually, using if statements where necessary to determine what gets pushed.

answered Nov 21, 2012 at 23:42

user428517

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Comments

unsunghero · Accepted Answer · 2012-11-21 23:57:14Z

0

Use the ternary operator. With the ternary operator, this:

if($selector == true){
    $foo = 'something'; 
} else {
    $foo = 'something else';
}

can become this:

$foo = ($selector == true) ? 'something' : 'something else';

Your example code would look something like this:

$selector = true;    
$main_array = array(
    'general' => array(
         'another_array' => array(
              'option1' => array(
                    'title' => 'Some Title',
                    'type' => 'select',
                    'option2' => ($selector == true) ? array('title' = 'Some title','type' = 'select') : array('title' => 'Some other title', 'type' => 'Some other type')
                ...

answered Nov 21, 2012 at 23:57

unsunghero

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Comments

Gilbert · Accepted Answer · 2012-11-22 00:47:47Z

0

Well, if you heart is set on using if/else rather than a ternary you can work some of the results out a bit early.

       if ($selector == true) {
    $preset2 = array(
     'title' = 'Some title',
     'type' = 'select'
     );
    }
    else
    {
     $preset2 = array( ... );
    }

 $main_array = array(
  'general' = array(
   'another_array' = array(
    'option1' = array(
     'title' = 'Some Title',
     'type' = 'select' ),
    'option2' = $preset2,

answered Nov 22, 2012 at 0:47

Gilbert

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