Change key name in nested JSON structure

Question

I have a JSON data structure as shown below:

{
    "name": "World",
    "children": [
      { "name": "US",
          "children": [
           { "name": "CA" },
           { "name": "NJ" }
         ]
      },
      { "name": "INDIA",
          "children": [
          { "name": "OR" },
          { "name": "TN" },
          { "name": "AP" }
         ]
      }
 ]
};

I need to change the key names from "name" & "children" to say "key" & "value". Any suggestion on how to do that for each key name in this nested structure?

...and why do you have a semicolon at the end? What exactly are you representing in the question? — I Hate Lazy
– I Hate Lazy, Commented Nov 22, 2012 at 19:33

I Hate Lazy · Accepted Answer · 2012-11-22 19:27:26Z

17

I don't know why you have a semicolon at the end of your JSON markup (assuming that's what you've represented in the question), but if that's removed, then you can use a reviver function to make modifications while parsing the data.

var parsed = JSON.parse(myJSONData, function(k, v) {
    if (k === "name") 
        this.key = v;
    else if (k === "children")
        this.value = v;
    else
        return v;
});

DEMO: http://jsfiddle.net/BeSad/

answered Nov 22, 2012 at 19:27

I Hate Lazy

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5 Comments

user1842231 Over a year ago

thank you. your code is working perfect. Sorry for semicolon at the end. It was a typo, but I've learned so much from this mistake.

user1739825 Over a year ago

@IHateLazy: I see something new like changing the key but may I know where is this function so that I can more in details. And if I want to add number to the key in the for loop, I seem can't get it to work like -- this.batchi.concat(string(i)) = v; where i is incrementing in the for loop.

user1739825 Over a year ago

@IHateLazy: Please refer to link.

daniel p Over a year ago

Does anyone know why dots cannot be replaced in the key name, but any other letter can? jsfiddle.net/dpiret/dgk5fp16/5

targumon Over a year ago

@danielp why did you use k.search? That function works with regex (so providing it with '.' gave you unexpected results. You probably wanted to use k.indexOf('.')

loganfsmyth · Accepted Answer · 2012-11-22 19:17:19Z

0

Try this:

function convert(data){
  return {
    key: data.name,
    value: data.children.map(convert);
  };
}

Or if you need to support older browsers without map:

function convert(data){
  var children = [];
  for (var i = 0, len = data.children.length; i < len; i++){
    children.push(convert(data.children[i]));
  }

  return {
    key: data.name,
    value: children
  };
}

answered Nov 22, 2012 at 19:17

loganfsmyth

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Comments

Denys Séguret · Accepted Answer · 2012-11-22 19:22:58Z

0

You could use a function like this :

function clonerename(source) {
    if (Object.prototype.toString.call(source) === '[object Array]') {
        var clone = [];
        for (var i=0; i<source.length; i++) {
            clone[i] = goclone(source[i]);
        }
        return clone;
    } else if (typeof(source)=="object") {
        var clone = {};
        for (var prop in source) {
            if (source.hasOwnProperty(prop)) {
                var newPropName = prop;
                if (prop=='name') newPropName='key';
                else if (prop=='children') newPropName='value';
                clone[newPropName] = clonerename(source[prop]);
            }
        }
        return clone;
    } else {
        return source;
    }
}

var B = clonerename(A);

Note that what you have isn't a JSON data structure (this doesn't exist as JSON is a data-exchange format) but probably an object you got from a JSON string.

edited Nov 22, 2012 at 19:22

answered Nov 22, 2012 at 19:12

Denys Séguret

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4 Comments

I Hate Lazy Over a year ago

The only thing I see that would disqualify it as valid JSON markup is the semicolon (I have no idea why that's there). Other than that, why wouldn't this be valid JSON?

Denys Séguret Over a year ago

Because JSON is a string format. This is probably a simple javascript object, it's only missing some var a = before. hence the ;.

I Hate Lazy Over a year ago

dystroy: Yes, JSON is a text format, but that doesn't mean this isn't some JSON markup sitting in a file on the server, again except for that semicolon. It's really not valid either way as shown.

I Hate Lazy Over a year ago

...but I guess I'd agree that the ; could make me lean that way.

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