Hibernate - How to set lazy property dynamically through coding

Question

I set lazy property as "true" in my hbm mapping file. However I want to change "lazy=false" dynamically through code. how can I achieve this?

Stanislav Bashkyrtsev · Accepted Answer · 2012-11-23 18:33:02Z

1

You can use either joins via HQL or FetchMode.JOIN via Criteria API, in this case you'll get your associations in a single shot. Note, that associated objects won't be fetched from 2nd level cache if you use it.

Another option is Hibernate.initialize() or simply just invoke object.getAssociation().

answered Nov 23, 2012 at 18:33

Stanislav Bashkyrtsev

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mindas · Accepted Answer · 2012-11-23 22:48:52Z

0

Look at sessionFactory.getClassMetadata(YourClass.class). It has the methods to access every field.

The more civilized way, however, is to override fetching strategy with HQL or Criteria query. Another option is to modify your metadata (having lazy="false") and rebuild the session factory. It's not that scary as it looks like.

answered Nov 23, 2012 at 22:48

mindas

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