What is the use of prototype in array.prototype.slice.call

Question

Why to include a prototype?

Why just not?

   Array.slice.call()

KooiInc · Accepted Answer · 2012-11-26 08:41:22Z

1

Array is a constructor function and doesn't contain a slice method. It's prototype (Array.prototype) does. You can however call slice from an (empty) Array instance :

[].slice.call(/*...*/)

answered Nov 26, 2012 at 8:41

KooiInc

124k32 gold badges145 silver badges181 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

melpomene · Accepted Answer · 2012-11-26 08:22:55Z

1

Because Array is a function and functions don't have a .slice method, only arrays do.

answered Nov 26, 2012 at 8:22

melpomene

86.2k8 gold badges96 silver badges155 bronze badges

Comments

arvin_codeHunk · Accepted Answer · 2012-11-26 08:27:52Z

1

Better check documentation ,this could help you http://shifteleven.com/articles/2007/06/28/array-like-objects-in-javascript

answered Nov 26, 2012 at 8:27

arvin_codeHunk

2,4208 gold badges35 silver badges48 bronze badges

Collectives™ on Stack Overflow

What is the use of prototype in array.prototype.slice.call

3 Answers 3

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related