['string1', 'string2'].join(',') // "string1,string2"
How can I obtain the following result?
"string1", "string2"
I am using underscore and jquery.
My goal is to make something like that:
_.without(['string1', 'string2', 'string3'], "string1", "string2");
=> ['string3']
For you case you don't need a "free" list of elements.
You just need to use _.difference instead of _.without.
_.difference(['string1', 'string2', 'string3'], ["string1", "string2"]);
You can't have a "free" list of elements. That's not how Javascript works. You always deal with arrays, collections and that sort of things.
I don't know Underscore.js very well, but try this:
var a = ['string1', 'string2', 'string3'],
b = ['string1', 'string2'];
_.without.apply(_, [a].concat(b));
The purpose of apply is to call a function with a dynamical number of dynamic arguments.
you could get it like this:
var something = '"' + ['string1', 'string2'].join('", "') + '"';
wich would result in: "string1", "string2"
alternately you could use JSON.stringify(['string1', 'string2'])
wich would result in: ["string1","string2"]
another way is to write a simple function which removes an array of strings from another, sth like
var arr = ["str1","str2","str3"];
function removeStrings(a,strs) {
strs.forEach(function(e) {
a.splice(a.indexOf(e),1);
});
}
removeStrings(arr,["str2","str1"]);
console.log(arr);//["str3"]
difference looks like better fit http://underscorejs.org/#difference
var rem, orig, val;
rem = ['string1', 'string2'];
orig = ['string1', 'string2', 'string3'];
val = _.difference(orig, rem); // ['string3'];
http://jsbin.com/eyegoh/1/edit
or little bit longer with jQuery using http://api.jquery.com/jQuery.grep/ and http://api.jquery.com/jQuery.inArray/
var rem, orig, val;
rem = ['string1', 'string2'];
orig = ['string1', 'string2', 'string3'];
val = $.grep(orig, function(el, ix) {
return $.inArray(el, rem) == -1;
});
