Java regex to match a pattern

Question

I am new to Java. I would like to write a Java regex to match a pattern and retrieve the value. I need to match the pattern below:

\# someproperty=somevalue // this is a new property

\#someproperty=somevalue // this is a new property

I have to match the above patterns (which may contains spaces) and I need to retrieve "someproperty" and "somevalue".

I tried with the pattern below, but it just matches only someproperty=somevalue , without "#" at the beginning. What can I try next?

Pattern propertyKeyPattern = Pattern.compile("^\\s*(\\S+?)\\s*=.*?");

Is # this is a new property a part of string? Or a comment? — Rohit Jain
– Rohit Jain, Commented Nov 27, 2012 at 6:13
You don't need a reluctant matching at the end. Just remove ? and add $ to it. BTW, if you are using Matcher.matches, then the anchors are implicit, you don't need to put them. — Rohit Jain
– Rohit Jain, Commented Nov 27, 2012 at 6:16

Kleenestar · Accepted Answer · 2012-11-27 06:47:50Z

2

If you want to match the whole string and find patterns, such as "\# someproperty =some value". Try regular Expression

^\\#\s*(\S+?)\s*=(.*)$

as Java string, it is

"^\\\\#\\s*(\\S+?)\\s*=(.*)$"

The match result for string \# someproperty = a some value is

matches() = Yes

find()    = Yes

group(0)  = \# someproperty = a some value

group(1)  = someproperty

group(2)  = a some value

answered Nov 27, 2012 at 6:47

Kleenestar

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Comments

Kanagaraj M · Accepted Answer · 2012-11-27 06:29:12Z

0

String a=yourString.replaceAll("[^\w\s]"," "); By using this you will get "someproperty" and "somevalue" string then u can check it. For more post your question clearly.

answered Nov 27, 2012 at 6:29

Kanagaraj M

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