How can I send grep results into a different output file for each input file?

Question

I have a folder that contains text files. I need to extract lines that has 'BA' from these text files . I used grep command to print the lines with BA. I would like to save the outputs to another folder with the same file names. How can I change the following code?

grep "  BA  "  dir/*.txt

Brian Agnew · Accepted Answer · 2012-11-29 16:01:09Z

2

for i in dir/*.txt; do
   grep "  BA  " $i > $newdir/`basename $i`
done

Note the use of basename, which takes dir/a.txt (say) and returns a.txt

answered Nov 29, 2012 at 16:01

Brian Agnew

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Comments

Thor · Accepted Answer · 2012-11-29 19:57:44Z

1

Sounds like a job for GNU parallel:

parallel --dry-run grep '"  BA  "' '{} > otherdir/{/}' ::: dir/{a,b,c}.txt

Output:

grep "  BA  " dir/a.txt > otherdir/a.txt
grep "  BA  " dir/b.txt > otherdir/b.txt
grep "  BA  " dir/c.txt > otherdir/c.txt

Remove --dry-run when you're happy with what you see.

{} is replaced by the inputs after ::: (these can also come from stdin or a file), {/} is the basename of {}.

answered Nov 29, 2012 at 19:57

Thor

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