javascript array to php array_sum()

Question

Cant seem to figure this out.. I have a JavaScript function that gets the value of all elements with the same class name:

var total = $(".bob").map(function() {
    return $(this).val();
}).get();

var queryString = "?total="+total;
http.open("GET", "product.php" + queryString, true);

http.onreadystatechange = rgetHttpRes;
http.send(null);

I am passing the array to my php file -

if (isset($_GET['total'])) {
    $price = $_GET['total'];
    $num = array($price);
    $result = array_sum($num);
    echo($result);
}

// So I passed 2 integers with the JavaScript function: 15.99 and 10.99 into this  php function.
   It will only return one of them:  10.99 //

When I do this:

if (isset($_GET['total'])) {
    $price = $_GET['total'];
    $num = array($price);
    print_r($num);
}

this is the output I get:

Array ( [0] => 15.99, 10.99 )

I can't figure out why it wont print them like

Array ( [0] => 15.99 [1] => 10.99 )

Does anyone have any ideas?

lostsource · Accepted Answer · 2012-12-01 19:53:41Z

4

The query is passed on as a string, you will need to use explode to convert it to an array

if(isset($_GET['total'])) {
    $price = $_GET['total'];
    $num = explode(",",$price);
    print_r($num);
}

edited Dec 1, 2012 at 19:53

answered Dec 1, 2012 at 19:46

lostsource

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1 Comment

user1764058 Over a year ago

Thanks, i thought i had tried that.. You saved me a headache!

user1794257 · Accepted Answer · 2012-12-01 19:49:37Z

0

how about this one ?

var t = $(".bob").size();
var ken = new Array();
var a;
for(a = 0;a<t;a++){
ken.push($(".bob").eq(a).val());
}

answered Dec 1, 2012 at 19:49

user1794257

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