Accessing files in specific folder in classpath using Java

Question

I want to read a bunch of text files in com.example.resources package. I can read a single file using the following code:

InputStream is = MyObject.class.getResourceAsStream("resources/file1.txt")
InputStreamReader sReader = new InputStreamReader(is);
BefferedReader bReader = new BufferedReader(sReader);
...

Is there a way to get the listing of file and then pass each element to getResourceAsStream?

EDIT: On ramsinb suggestion I changed my code as follow:

BufferedReader br = new BufferedReader(new InputStreamReader(MyObject.class.getResourceAsStream("resources")));
String fileName;
while((fileName = br.readLine()) != null){ 
   // access fileName 
}

I want to access files in classpath and not from a specific folder like C:\\resources. — Akadisoft
– Akadisoft, Commented Dec 12, 2012 at 20:52
Perhaps you want this: stackoverflow.com/questions/3923129/… — nwaltham
– nwaltham, Commented Dec 12, 2012 at 20:55
You can reuse code for this (after small modification) stackoverflow.com/questions/176527/… — CAMOBAP
– CAMOBAP, Commented Dec 12, 2012 at 20:59

Arjan Tijms · Accepted Answer · 2012-12-13 11:55:43Z

10

If you pass in a directory to the getResourceAsStream method then it will return a listing of files in the directory ( or at least a stream of it).

Thread.currentThread().getContextClassLoader().getResourceAsStream(...)

I purposely used the Thread to get the resource because it will ensure I get the parent class loader. This is important in a Java EE environment however probably not too much for your case.

edited Dec 13, 2012 at 11:55

Arjan Tijms

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answered Dec 12, 2012 at 21:06

ramsinb

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1 Comment

pstrag Over a year ago

Hi, I'm trying to use your answer. Can you help me with that: stackoverflow.com/questions/29430113/… ?

Community · Accepted Answer · 2017-05-23 12:15:00Z

This SO thread discuss this technique in detail. Below is a useful Java method that list files from a given resource folder.

/**
   * List directory contents for a resource folder. Not recursive.
   * This is basically a brute-force implementation.
   * Works for regular files and also JARs.
   * 
   * @author Greg Briggs
   * @param clazz Any java class that lives in the same place as the resources you want.
   * @param path Should end with "/", but not start with one.
   * @return Just the name of each member item, not the full paths.
   * @throws URISyntaxException 
   * @throws IOException 
   */
  String[] getResourceListing(Class clazz, String path) throws URISyntaxException, IOException {
      URL dirURL = clazz.getClassLoader().getResource(path);
      if (dirURL != null && dirURL.getProtocol().equals("file")) {
        /* A file path: easy enough */
        return new File(dirURL.toURI()).list();
      } 

      if (dirURL == null) {
        /* 
         * In case of a jar file, we can't actually find a directory.
         * Have to assume the same jar as clazz.
         */
        String me = clazz.getName().replace(".", "/")+".class";
        dirURL = clazz.getClassLoader().getResource(me);
      }

      if (dirURL.getProtocol().equals("jar")) {
        /* A JAR path */
        String jarPath = dirURL.getPath().substring(5, dirURL.getPath().indexOf("!")); //strip out only the JAR file
        JarFile jar = new JarFile(URLDecoder.decode(jarPath, "UTF-8"));
        Enumeration<JarEntry> entries = jar.entries(); //gives ALL entries in jar
        Set<String> result = new HashSet<String>(); //avoid duplicates in case it is a subdirectory
        while(entries.hasMoreElements()) {
          String name = entries.nextElement().getName();
          if (name.startsWith(path)) { //filter according to the path
            String entry = name.substring(path.length());
            int checkSubdir = entry.indexOf("/");
            if (checkSubdir >= 0) {
              // if it is a subdirectory, we just return the directory name
              entry = entry.substring(0, checkSubdir);
            }
            result.add(entry);
          }
        }
        return result.toArray(new String[result.size()]);
      } 

      throw new UnsupportedOperationException("Cannot list files for URL "+dirURL);
  }

Anton Hell · Accepted Answer · 2012-12-12 21:52:26Z

0

I think thats what you want:

String currentDir = new java.io.File(".").toURI().toString();
// AClass = A class in this package
String pathToClass = AClass.class.getResource("/packagename).toString();
String packagePath = (pathToClass.substring(currentDir.length() - 2));

String file;
File folder = new File(packagePath);
File[] filesList= folder.listFiles(); 

for (int i = 0; i < filesList.length; i++) 
{
  if (filesList[i].isFile()) 
  {
    file = filesList[i].getName();
    if (file.endsWith(".txt") || file.endsWith(".TXT"))
    {
      // DO YOUR THING WITH file
    }
  }
}

edited Dec 12, 2012 at 21:52

answered Dec 12, 2012 at 20:52

Anton Hell

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2 Comments

CAMOBAP Over a year ago

How do you plan get File object from package name String?

Akadisoft Over a year ago

I tried File folder = new File("/com/example/resources") and it is throwing NullPointerException

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