preg_match issues using php variable

Question

I have a variable I want to use in a preg_match combined with some regex:

$string = "cheese-123-asdf";
$find = "cheese";
if(preg_match("/$find-/d.*/", $string)) {
    echo "matched";
}

In my pattern I am trying to match using cheese, followed by a - and 1 digit, followed by anything else.

Jeffrey Bosboom · Accepted Answer · 2015-03-14 00:46:51Z

4

change /d to \d
there is no need to use .*
if your string is defined by user (or may contains some characters (e.g: / or * or ...)) this may cause problem on your match.

Code:

<?php
$string = "cheese-123-asdf";
$find = "cheese";
if(preg_match("/$find-\d/", $string)) 
{
    echo "matched";
}
?>

Jeffrey Bosboom

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answered Dec 13, 2012 at 21:17

Shahrokhian

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Comments

Explosion Pills · Accepted Answer · 2012-12-13 20:42:09Z

3

You mistyped / for \:

if(preg_match("/$find-\d.*/", $string)) {

The .* is also not really necessary since the pattern will match either way.

answered Dec 13, 2012 at 20:42

Explosion Pills

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jaudette · Accepted Answer · 2012-12-13 20:42:13Z

1

for digit, it's \d

if(preg_match("/$find-\d.*/", $string)) {

answered Dec 13, 2012 at 20:42

jaudette

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