Trying to fill a PHP array

Question

On a previous page, I have gotten the names and the number of playeys values from the user.

I wish to fill them into an array. Here is my code so far:

<?php

$numberOfPlayers = $_POST['numberOfPlayers'];
$counter = 1;
$playerName = array();

while($counter<=$numberOfPlayers-1){
$playerName[$counter-1]= $_POST[$counter];
$counter=$counter+1;
}  

print_r($playerName);

?>

However it is throwing out an error saying "Undefined offset: 1 in C:\wamp\www\test.php on line 8".

Any help would be much appreciated.

Thanks

$_POST['1'] does not exist.

Wrikken
– Wrikken

2012-12-14 19:40:24 +00:00
Commented Dec 14, 2012 at 19:40 — Wrikken
– Wrikken, Commented Dec 14, 2012 at 19:40

Shiplu Mokaddim · Accepted Answer · 2012-12-14 19:51:42Z

3

Just use array_push(). or [] array short hand. No need to use a counter.

while($numberOfPlayers--){
    if(isset($_POST[$numberOfPlayers]))
        $playerName[]= $_POST[$numberOfPlayers];
}

edited Dec 14, 2012 at 19:51

answered Dec 14, 2012 at 19:38

Shiplu Mokaddim

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5 Comments

spogebob92 Over a year ago

This isn't exactly what I want. I need to populate the array so I need the counter. There are many player names, but the amount of players vary depending on what the user has chossen on the previous screen.

Shiplu Mokaddim Over a year ago

Does $_POST['numberOfPlayers'] contain the total number of players or total selected number for players?

spogebob92 Over a year ago

It contains the total number of players.

spogebob92 Over a year ago

This also doesnt work. This would only assign the numberofplayer to the playerName array. I want the names stored in the playerName array. Thanks for the help though man.

Shiplu Mokaddim Over a year ago

could you show what does var_dump($_POST) contain. You must show your data layout. Otherwise I can not code just blindly.

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