In Yii how to display image as output whose path is stored in database

Question

I am creating a project in Yii. I am having table as Dnymedia with fields as,

Dnymedia

-mediaId

-mediaPath

-contentTitleId

Suppose I have media path stored as="F:\Documents and Settings\All Users\Documents\My Pictures\Sample Pictures"

How do I display this image as output? I don't need to display it in view. I just want to display the image as output of the controller's action in Yii.

if you got your answer please accept it, or let me know if any question — hemc4
– hemc4, Commented Dec 19, 2012 at 8:27

hemc4 · Accepted Answer · 2012-12-19 08:09:37Z

1

instead of read file use file_get_contents

header('Content-Type: image/jpeg');
echo file_get_contents('F:\Documents and Settings\All Users\Documents\My Pictures\Sample.jpg');
die;

answered Dec 19, 2012 at 8:09

hemc4

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Comments

Kapil gopinath · Accepted Answer · 2012-12-19 06:23:14Z

0

This worked for me.Please check it.

public function actionTest()
    {
        header('Content-Type: image/jpeg');
        readfile('http://localhost/myAppetite/images/bodyBg.jpg');
         die;
    }

answered Dec 19, 2012 at 6:23

Kapil gopinath

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1 Comment

user1636115 Over a year ago

Sir i had tried as above. But its not displaying image,just thumbnail is displayed.....

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