Bash interpreter change arguments order

Question

I have bash script and try run command inside it

That's ok

echo ${something:="zip -r -q $TAG -P $PASS $LOCPATH"}
>zip -r -q evolution -P evolution ~/.gconf/apps/evolution

That's ok too

zip -r -q evolution -P evolution ~/.gconf/apps/evolution

But here order have been changed only when passed values and added strange . -i

zip -r -q $TAG -P $PASS $LOCPATH
>zip error: Nothing to do! (try: zip -r -q -P evolution evolution . -i ~/.gconf/apps/evolution

Thanks for any advice.

Ignacio Vazquez-Abrams · Accepted Answer · 2012-12-22 20:15:07Z

3

something=(zip -r -q "$TAG" -P "$PASS" "$LOCPATH")
"${something[@]}"

answered Dec 22, 2012 at 20:15

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Comments

Gilles Quénot · Accepted Answer · 2012-12-22 19:09:23Z

0

Try doing type zip, seems it's aliased to something.

Maybe put the full path of zip to override this ,something like :

/usr/bin/zip

answered Dec 22, 2012 at 19:09

Gilles Quénot

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Sorry man. I have been edited question. Zip works ok if not passed $params.

Not aliased.type zip > zip is hashed (/usr/bin/zip)