I am not soo good in RegEx. Can somebody help me to to replace
<MessageParam name="0" desc="Source Queue" />
with
<MessageParam name="0" desc="Source Queue"></MessageParam>
using regular expression
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1You should try using JDom instead.ecbrodie– ecbrodie2012-12-25 05:55:02 +00:00Commented Dec 25, 2012 at 5:55
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don't use regex to parse HTMLggorlen– ggorlen2023-01-09 22:35:18 +00:00Commented Jan 9, 2023 at 22:35
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4 Answers
Regex to match:
(<\s*MessageParam[^>]*)/\s*>
Replacement string:
$1></MessageParam>
You may need to escape the \ character (add an extra \ before it).
I assume > does not appear in the value for the attributes, and the XML is valid.
More generalized version:
Regex to match:
<\s*([^\s>]+)([^>]*)/\s*>
Replacement string:
<$1$2></$1>
For this one, I'm not sure of all the assumptions that I have made. But I still assume > does not appear in the value for the attributes, and the XML is valid.
2 Comments
nhahtdh
I'm not sure if XML parser can change the type of closing tag. It is better to use XML parser to do so if possible.
Rick Mac Gillis
For those of you looking for the inverse of this question, you can use the following code to replace open/close empty tags with self-closing tags. Find:
<([A-Z][A-Z0-9]*)\b[^>]*>(.*?)</\1> Replace it with: <$1/> (Thanks to thetopsites.net/article/51312414.shtml)Regex
<(\w+)(.+?)/>
replace with
<$1$2></$1>
4 Comments
jcvandan
This just really helped me, as the accepted answer produced some occasionally strange results
5260452
This doesn't work on nested DOM elements, unfortunately.
hbertsch
Perfect! Exactly what I was looking for. Just use this in Notepad++ with the find and replace feature and you are done :)
Jay Gray
saved me hours of wasted effort
public static void format(String xmlNode) {
Pattern patt = Pattern.compile("(<MessageParam[^>]*)(\\s*/>)");
Matcher mattcher = patt.matcher(xmlNode);
while (mattcher.find()){
String result = mattcher.replaceAll("$1></MessageParam>");
System.out.println(result);
}
}
3 Comments
nhahtdh
A simple
replaceAll in String class will do, not sure why you go through all the trouble of writing Pattern/Matcher loop.
user864309
nhahtdh - I don't understand how a replaceAll will help if i have multiple strings with different 'desc'
prageeth
xmlString.replaceAll("(<MessageParam[^>]*)(\\s*/>)", "$1></MessageParam>");This worked for me:
xmlString.replaceAll("<(\\w*:*\\w+)/>", "<$1></$1>");
1 Comment
Community
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