Push to array and create running total

Question

I need to push the height of each page into an array. However the/my problem is, that I need to push not the values themselves, but a running total of the values.

Here's what I've done so far:

var heights = [0];
$('.page').each(function(i) {
    heights.push($(this).height());
});

The result looks like this: [0, 2000, 1000, 3000, 1500], which is the heights of the pages, but I need something like this: [0, 2000, 3000, 6000, 7500], which is the running total of the page heights added.

do you mean [2000, 3000, 6000, 7500]?

Joseph Marikle
– Joseph Marikle

2012-12-28 22:38:50 +00:00
Commented Dec 28, 2012 at 22:38 — Joseph Marikle
– Joseph Marikle, Commented Dec 28, 2012 at 22:38
so you want it sorted? just use .sort(); after inserting.

kennypu
– kennypu

2012-12-28 22:41:07 +00:00
Commented Dec 28, 2012 at 22:41 — kennypu
– kennypu, Commented Dec 28, 2012 at 22:41
@JosephMarikle Whoops, yes! :P

yckart
– yckart

2012-12-28 22:41:15 +00:00
Commented Dec 28, 2012 at 22:41 — yckart
– yckart, Commented Dec 28, 2012 at 22:41

aefxx · Accepted Answer · 2012-12-28 22:48:41Z

3

var heights = [0];
$('.page').each(function(i) {
    heights.push(
        $(this).height() + (heights[i] || 0)
    );
});

EDIT
Edited version now incorporates the leading 0 array member as requested by the questioner.

edited Dec 28, 2012 at 22:48

answered Dec 28, 2012 at 22:43

aefxx

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Comments

Dancrumb · Accepted Answer · 2012-12-28 22:41:35Z

2

You can do it in a single loop:

var heights = [];
var total   = 0;
$('.page').each(function(i) {
    total += $(this).height();
    heights.push(total);
});

Or... if you want it to be super clean:

var heights = [];
var total   = 0;
$('.page').each((function(){
  var total = 0;
  return function(i) {
    total += $(this).height();
    heights.push(total);
  };
}()));

The second version avoids polluting any scopes with the total variable.

answered Dec 28, 2012 at 22:41

Dancrumb

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1 Comment

Krease Over a year ago

The leading 0 doesn't really change much of the answer.

Lee Meador · Accepted Answer · 2012-12-28 22:54:28Z

2

Add this after the code you have:

var total = 0;
for (i=1 ; i < heights.length ; ++i) {
    total += heights[i];
    heights[i] = total;
}

edited Dec 28, 2012 at 22:54

answered Dec 28, 2012 at 22:39

Lee Meador

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1 Comment

Lee Meador Over a year ago

@yckart There. Fixed that.

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