String/Array checking php

Question

How can I check if the first 2 characters of an array are 0x? here is an example:

$hex = "0xFFFF";
if($hex[0:2].find('0x')==0)
{
print("0x Found.");
}
else
{
print("0x Not Found.");
}

Can anyone create an alternative that works?

Are you really talking about an array? $hex in your example is a string. — Wolfgang Stengel
– Wolfgang Stengel, Commented Dec 28, 2012 at 23:49
The first two characters of an array or string? In PHP these are different things (thought they do have the concept of array access for strings) — Mike Brant
– Mike Brant, Commented Dec 28, 2012 at 23:49
$hex[0:2] - PHP does not have nice stuff like that. Consider using Python if you like having a nice operator to get a slice from a string. — ThiefMaster
– ThiefMaster, Commented Dec 28, 2012 at 23:50
I was just using a string as an example but the solution is pretty much the same for an array. — Tod
– Tod, Commented Dec 28, 2012 at 23:54

Mike Brant · Accepted Answer · 2012-12-28 23:50:53Z

1

If $hex is a string this is rather easy

if (strpos($hex, '0x') === 0) {
    print("0x Found.");
} else {
    print("0x Not Found.");
}

answered Dec 28, 2012 at 23:50

Mike Brant

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Comments

Alain · Accepted Answer · 2012-12-28 23:50:59Z

1

Using strnicmp (manual) looks good.

$hex = '0xFFFF';
if (strnicmp($hex, '0x', 2) == 0)
{
    print("0x Found.");
}
else
{
    print("0x Not Found.");
}

Looks for an insensitive '0x' string at the beginning of your $hex var.

answered Dec 28, 2012 at 23:50

Alain

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Comments

score 1 · Accepted Answer · 2012-12-28 23:59:23Z

1

$hex = '0xFFFF';
if ($hex[0].$hex[1] == '0x')
{
    print("0x Found.");
}
else
{
    print("0x Not Found.");
}

Without needing to use any function. See this page for it's usage.

edited Dec 28, 2012 at 23:59

answered Dec 28, 2012 at 23:49

user1592648

Comments

None · Accepted Answer · 2012-12-29 00:56:39Z

0

You can access string characters as an array to get the first and second index and check if they are 0 and x.

<?php
$hex = array("0xFFF","5xFFF","0xDDD");
$len = count($hex);
$msg = "";
for ($i = 0; $i < $len; $i++) {
    if ($hex[$i][0] == "0" && $hex[$i][1] == "x") {
        $msg .= $hex[$i] . ' starts with 0x!' . "\n";
    }
}
echo ($msg);
?>

edited Dec 29, 2012 at 0:56

None

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answered Dec 29, 2012 at 0:15

ECode

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