How to deserialize from xml file to object list in java?

Question

The following code doesn't work. I got exception when I run these line[Object objPoints = serializer.read(Point.class, file);] In details, the source attachment doesn't contain the source for the Persister.class.

import org.simpleframework.xml.Serializer; 
import org.simpleframework.xml.core.Persister;
import java.io.File;

Serializer serializer = new Persister();
File file = new File("1.xml");
Object objPoints = serializer.read(Point.class, file);

Point Class is as follow :

@Root
public class Point {
   @Element
   private float X;
   @Element
   private float Y;
}

I references from this link.

Also i am almost convinced the method will be called read not rea and file will be passed in without the leading >. Make sure you post your real code, please. — Boris Strandjev
– Boris Strandjev, Commented Jan 2, 2013 at 10:39
@Boris,I import [import org.simpleframework.xml.Serializer; import org.simpleframework.xml.core.Persister;] — Yu Li Shein
– Yu Li Shein, Commented Jan 2, 2013 at 10:42
What does "Serialization doesn't work." mean? Are you getting an exception? — blank
– blank, Commented Jan 2, 2013 at 10:44
Also include the content of the xml file you are trying to parse — Boris Strandjev
– Boris Strandjev, Commented Jan 2, 2013 at 10:45

ollo · Accepted Answer · 2013-01-03 22:50:58Z

1

If i use the xml from your comment and your code it works:

XML:

<Point>
   <X>2</X>
   <Y>3</Y>
</Point>

But in the title of this question you talk about "object list" - can you be more detailed here?

If you need do deserialize a list of Points you cant use the Point class but a list.

Btw. does your xml file contain any additional content or only this one point?

answered Jan 3, 2013 at 22:50

ollo

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2 Comments

Yu Li Shein Over a year ago

Really? I don't know what's the problem. My code does work for me. Actually I need to read the list of object. But I couldn't read one object. After reading one obeject successfully, I wonna try the list of object.

ollo Over a year ago

You can't read only one Point out of a XML Point List (eg. <points><point>..</point><point>..</point></points>). But what you can do is creating a PointList class which contains a list of Points. Such a list (incl. all objects in it) can be deserialized.

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