Remove string unless there is a space

Question

I have this regular expression, I would like it to remove all text between $ and $ and replace it with an empty string, UNLESS there is a space anywhere between the two $ signs, and in that case ignore the replacement. With the regexp that I have now, it removes it no matter if there is a space or not.

<?php
$tmp = "<p>
    $random_text$
</p>
<p>
    $random text2$
</p>
<p>
    This is some text
</p>
<p>
    This is some text
</p>";

$tmp = preg_replace("/\\$[^ ].+?\\$/", "", $tmp);

So, in the end I would like to have this as the output. As you may notice, the text between the first paragraph tags are gone, but second one still stands.

<p>

</p>
<p>
    $random text2$
</p>
<p>
    This is some text
</p>
<p>
    This is some text
</p>

Helio Santos · Accepted Answer · 2013-01-02 16:25:41Z

1

/\\$[^ ]+?\\$/

I've just removed the dot

answered Jan 2, 2013 at 16:25

Helio Santos

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4 Comments

Kyle Strand Over a year ago

This will just remove a single non-space character.

Helio Santos Over a year ago

@RyanNaddy only one space is ok?

Get Off My Lawn Over a year ago

1+, but this seem to cover that.

Kyle Strand Over a year ago

Sorry, I wasn't thinking earlier. This should work. Though it might be preferable to put $ in the negative character class as well, to ensure that you are matching consecutive occurrences of $.

Pawan Thakur · Accepted Answer · 2013-01-02 17:12:14Z

0

<?php $source = 'His $name$ is $Luis$';
echo $result = preg_replace('/\$(.*?)\$/', '<b>$1</b>', $source);
?>

answered Jan 2, 2013 at 17:12

Pawan Thakur

5918 silver badges19 bronze badges

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