mysql: command not found but it is in my PATH

Question

.bashrc says:

PATH=$PATH:/usr/local/mysql/bin/:$HOME/.rvm/bin # Add RVM to PATH for scripting

but mysql -u root returns

-bash: mysql: command not found

but if I do /usr/local/mysql/bin/mysql -u root everything works fine. Why isn't it search using PATH?

Thanks

If you do echo $PATH in a shell, do you see the changed PATH? If not, I might know why. — cdhowie
– cdhowie, Commented Jan 4, 2013 at 15:54
@fge That's what I think is going on, I have an answer drafted that I will post. — cdhowie
– cdhowie, Commented Jan 4, 2013 at 16:00

cdhowie · Accepted Answer · 2013-01-04 16:00:39Z

1

You need to either use:

export PATH=$PATH:...

Or add the export PATH statement after this statement.

The changes you are making are not surviving beyond the execution of your .bashrc. Adding export before your assignment (or export PATH) later will ensure that your changes are exported to your shell's child processes.

answered Jan 4, 2013 at 16:00

cdhowie

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2 Comments

0xSina Over a year ago

Thanks. Also has to do source ~/.bashrc to reload the file after saving.

that other guy Over a year ago

Unexported variables do survive beyond the execution of .bashrc, and $PATH is used by the shell itself so it doesn't need to be exported to work. But unexported, it would not show up in su or screen or other child processes as you mentioned.

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