PHP - echo inside an echo

Question

I have a PHP if/else statement. This is the code I'm trying to echo under an else condition.

<?php $locked = ForumData::is_topic_locked($post->topic_id);
            if ($locked->topic_locked == 1) {echo '<td align="right"><font color="#FF0000">Topic Locked</font><td>';}
            else { 
            echo '<td align="left"><a href="'.url('Forum/create_new_post?topic_id='.$post->topic_id.'&forum_id='.$post->forum_id.'').'"><img src="<?php echo SITE_URL?>/lib/skins/flyeuro/images/forums/t_reply.gif"/></a></td>'; }
            ?>

The bit I'm interested to echo is this.

<img src="<?php echo SITE_URL?>

If I try this... 'echo SITE_URL'

Parse error: syntax error, unexpected T_ECHO, expecting ',' or ';'

But this doesn't parse the image, and if I try parsing anything else, it's giving me parsing errors, which I can't fix?

How can I therefore produce an echo inside another echo?

You have } at the end - where does it belong to? And the if-else statement is missing. — hakre
– hakre, Commented Jan 5, 2013 at 23:32
The } closes the else statement. I'll edit my main post for clarity. — zzwyb89
– zzwyb89, Commented Jan 5, 2013 at 23:33
I have problems to follow your quesiton, I can not reproduce that parse error. Probably that is to some other code. See here your code in many PHP versions: 3v4l.org/b4NtM — hakre
– hakre, Commented Jan 5, 2013 at 23:45

Community · Accepted Answer · 2017-05-23 10:27:19Z

3

why did you open a <?php tag again, you are already in echo line?

echo '<td align="left"><a href="'.url('Forum/create_new_post?topic_id='.$post->topic_id.'&forum_id='.$post->forum_id.'').'"><img src="'.SITE_URL.'/lib/skins/flyeuro/images/forums/t_reply.gif"/></a></td>';

and what is SITE_URL? Is that a variable, did you forget to put $?

echo prints out the string that you gave as parameter,

echo "foo";

As @hakre mentioned about it, . is used to concatenate strings.

$var = "foo"."bar";  //foobar

So you can use it in echo line,

$var = "foo"."bar";  //foobar
echo "foo "."bar ".$var // foo bar foobar

And It's not important weather variable defined as a string. It would be a constant variable.

define('SITE_URL', 'localhost:8080/phpvms'); 
echo "my website URL is ".SITE_URL; //my website URL is localhost:8080/phpvms

edited May 23, 2017 at 10:27

CommunityBot

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answered Jan 5, 2013 at 23:43

Okan Kocyigit

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3 Comments

zzwyb89 Over a year ago

Could you explain to me for future reference what the dots do in PHP if you don't mind? The SITE_URL is a string of the website address gained from a config.php file in a CMS. It is setup during the CMS installation. i.e. define('SITE_URL', 'localhost:8080/phpvms');

hakre Over a year ago

A dot in PHP is used to concatenate two strings. php.net/manual/en/language.operators.string.php - that define defines a constant (as a string), so you can use the dots here to contanate strings with strings. In my answer I just use echo with multiple string expressions separated by a comma, that is similar but also different: stackoverflow.com/a/14177712/367456 - a bit special to echo.

zzwyb89 Over a year ago

Thank you for the full explanation, just got an example sorted and working to enhance my humble PHP knowledge :)

Head · Accepted Answer · 2013-01-05 23:36:07Z

1

Remember:

<?php echo "<a href=\"$url\">View</a>"; ?>

" and \

this!

Hope that's enough of a hint!@

answered Jan 5, 2013 at 23:36

Head

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4 Comments

zzwyb89 Over a year ago

Oh, is it that easy? Correct me if I'm wrong <img src="<?php echo \"SITE_URL\"?> ... ;>

Head Over a year ago

Might be that you need the double quotes around the html.

Head Over a year ago

maybe put the whole thing in an include file. might work as well. just adding my two cents.

JGallardo Over a year ago

Stackoverflow is not for "hints", explain your answer like the rest of us or don't bother posting

hakre · Accepted Answer · 2013-01-05 23:48:39Z

0

Your problem is probably solved this way:

echo '<td align="left"><a href="',
     url('Forum/create_new_post?topic_id=' . $post->topic_id . '&forum_id=' . $post->forum_id . '') ,
     '"><img src="', SITE_URL,
              #######################
     '/lib/skins/flyeuro/images/forums/t_reply.gif"/></a></td>';

In PHP you can use constants quite like variables, e.g. to output them. You don't need to stack echoes inside each other or something.

answered Jan 5, 2013 at 23:48

hakre

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