PHP is concatenating instead of adding

Question

I'm having this problem where my PHP code is concatenating instead of adding

$offset=$_POST['offset']; //Get the offset
$searchLimit = 10;
$searchCount = count(sql) //For the purpose of this question, it returns the result count

Now I want to calculate the 'from' display for pagination, so I do

$from = ($offset*$searchLimit)+1;

It works fine when

$offset == 0

I get the expected result which is 1. But when

$offset == 1

It gives me 101. Basically it is concatenating the 10 and 1 to give me 101. I've tried the following

$from = (int)($offset*$searchLimit)+1
$from = ((int)($offset)*$searchLimit)+1
$from = (((int)($offset)*$searchLimit)+1)

I even tried

$offset = (int)$_POST['offset'];

But all of them are giving the same result.

Have you looked at PHP's intval function? php.net/manual/en/function.intval.php — RageD
– RageD, Commented Jan 6, 2013 at 1:53
I have .. Actually tried it before writing this comment .. So this is what I tried ... $from = (intval($offset*$searchLimit)+1) but that doesn't help either .. — Prathamesh Datar
– Prathamesh Datar, Commented Jan 6, 2013 at 2:30
How is $from = ($offset*$searchLimit)+1; 'working fine' if it returns 0 as stated? (0*10)+1 == 1 surely? — Crisp
– Crisp, Commented Jan 6, 2013 at 3:52
Sorry .. Once again that was my mistake in asking the question .. It is returning 1 which is the expected result .. I will correct the same in the question .. I will also try putting the intval around $_POST['offset'] .. I had initially tried $offset = (int)$_POST['offset'] but that didn't do anything different .. — Prathamesh Datar
– Prathamesh Datar, Commented Jan 6, 2013 at 4:37

Niet the Dark Absol · Accepted Answer · 2013-01-06 01:56:21Z

4

You are missing a $ before searchLimit. As a result, it is being treated as a string. This result in unexpected behaviour.

answered Jan 6, 2013 at 1:56

Niet the Dark Absol

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2 Comments

PleaseStand Over a year ago

A dollar sign might also be missing before sql. If you had enabled PHP's display_errors setting and set error_reporting to include E_NOTICE, you would have quickly discovered this problem.

Prathamesh Datar Over a year ago

Sorry .. The missing '$' is a typo .. I do have it in my code .. The sql line is just a pseudo-line. It is not the actual LOC in the application. It is the line that returns the count of the search result.

mjsa · Accepted Answer · 2013-01-06 01:57:53Z

1

You missed a $ sign before searchLimit (and perhaps before sql). -_-

answered Jan 6, 2013 at 1:57

mjsa

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