Setting a variable to act as a function call

Question

I want to set a variable to either .prev() or .next(), for example:

   if(x == y)
       var shift = '.prev()';
   else
       var shift = '.next()';

   $("li.active").removeClass('active')shift.addClass('active');

I could probably get it working with eval() however it's a security hazard.

Am I missing something obvious?

Felix Kling · Accepted Answer · 2013-01-09 00:15:24Z

5

Every property of an object can be accessed by using bracket notation ^[spec].
foo.bar() is the same as foo['bar']():

if(x == y)
   var shift = 'prev';
else
   var shift = 'next';

// or a shorter and nicer way: 
// var shift = x == y ? 'prev' : 'next';

$("li.active").removeClass('active')[shift]().addClass('active');

edited Jan 9, 2013 at 0:15

answered Jan 9, 2013 at 0:09

Felix Kling

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4 Comments

Madbreaks Over a year ago

shift declaration is out of scope, no?

Felix Kling Over a year ago

@Madbreaks: No. JavaScript only has function scope.

Madbreaks Over a year ago

Interesting. Ok, but how about var shift = x === y ? prev : next; :)

Felix Kling Over a year ago

@Madbreaks: Yep, I was just suggesting that ;)

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