String to date conversion

Question

Following code

 SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd-MMM-yy", new DateFormatSymbols(Locale.US));
        System.out.println(simpleDateFormat.parse("03-Apr-96"));

Gives output as Wed Apr 03 00:00:00 IST 1996

What should I do get the output like 1996-04-03 00:00:00.0

I have added a question at the bottom ,please suggest.I'm sorry for putting my question as an answer — Sinha
– Sinha, Commented Jan 10, 2013 at 11:00
Full reference of characters and examples are in SimpleDateFormat javadoc. docs.oracle.com/javase/6/docs/api/java/text/… — gaborsch
– gaborsch, Commented Jan 10, 2013 at 11:27

Obl Tobl · Accepted Answer · 2013-01-10 08:12:30Z

1

Try the following:

    SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd-MMM-yy", new DateFormatSymbols(Locale.US));
    Date d = simpleDateFormat.parse("03-Apr-96");  
    simpleDateFormat.applyPattern("yyyy-MM-dd HH:mm:ss.S");
    System.out.println(simpleDateFormat.format(d));

edited Jan 10, 2013 at 8:12

answered Jan 10, 2013 at 8:05

Obl Tobl

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asermax · Accepted Answer · 2013-01-10 08:08:02Z

0

A DateFormat object can be either used to parse a String into a Date object or the other way around. In your example, you're doing the former, when what you really want to do is to format your Date into a given pattern.

Here's an example of what you may want to do:

DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
System.out.print(df.format(yourDateObject));

answered Jan 10, 2013 at 8:08

asermax

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user1965351 · Accepted Answer · 2013-01-10 08:07:52Z

0

Try this:

SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd-MMM-yy", new DateFormatSymbols(Locale.US));
        Date date=simpleDateFormat.parse("03-Apr-96");

        SimpleDateFormat simpleDateFormat1 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S", new DateFormatSymbols(Locale.US));
        System.out.println(simpleDateFormat1.format(date));

answered Jan 10, 2013 at 8:07

user1965351

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