Writing a PHP if Blank statement

Question

I'm new to PHP so this will sound basic to most people but I need to write the code for when a variable returns nothing (blank).

My variable is $winner, but sometimes there is no winner, in this case it just leaves the page blank, I would like it so if there is no winner then it will display "no winner".

This is my attempt:

if empty($winner) {
    echo "no winner";
}

stackoverflow.com/questions/381265/…

001
– 001

2013-01-16 14:25:25 +00:00
Commented Jan 16, 2013 at 14:25 — 001
– 001, Commented Jan 16, 2013 at 14:25

Jigar Pandya · Accepted Answer · 2013-01-16 14:29:18Z

0

You can make a function to check the variable's valaue with null or empty...

function IsEmptyString($Season){
    return (!isset($Season) || trim($Season)==='');
}

This function can be used to check the same.

answered Jan 16, 2013 at 14:29

Jigar Pandya

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Alexandru Olaru · Accepted Answer · 2015-03-12 11:37:42Z

0

Just use:

if (!$winner) { // will catch "", null
    echo "no winner"
}

answered Mar 12, 2015 at 11:37

Alexandru Olaru

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