Im trying to search for nn/nnnnnn/nn in a file..
I have this
if (preg_match_all("([0-9]{6})", $file, $out)) {
echo "Match was found <br />";
print_r($out);
which deals with the centre 6 numbers but how do I get it to search for the whole pattern? I get a little confused when i have to add the search strings together. I know I have to do the following
([0-9]{2}) and / and ([0-9]{6}) and / and ([0-9]{2})
HOw do I add the search string as one? Thanks in advance Cheers Mat
You can also use \d for a digit instead:
preg_match_all("#(\d{2})/(\d{6})/(\d{2})#", $string, $matches);
print_r($matches);
Have you tried:
preg_match_all("/([0-9]{2})\/([0-9]{6})\/([0-9]{2})/")
If searching 12/123456/12, for example, it will output:
Array
(
[0] => Array
(
[0] => 12/123456/12
)
[1] => Array
(
[0] => 12
)
[2] => Array
(
[0] => 123456
)
[3] => Array
(
[0] => 12
)
)
preg_match_all("#([0-9]{2})/([0-9]{6})/([0-9]{2})#")
Try this #(\d{2})/(\d{6})/(\d{2})#:
$file = '23/334324/23';
if (preg_match_all("#(\d{2})/(\d{6})/(\d{2})#", $file, $out)) {
echo "Match was found <br />";
print_r($out);
}
Returns:
Array
(
[0] => Array
(
[0] => 23/334324/23
)
[1] => Array
(
[0] => 23
)
[2] => Array
(
[0] => 334324
)
[3] => Array
(
[0] => 23
)
)
How about using #([0-9]{2})/([0-9]{6})/([0-9]{2})#:
if(preg_match_all("#([0-9]{2})/([0-9]{6})/([0-9]{2})#", $file, $out))
{
echo "Match was found <br />";
print_r($out);
}
