Preg_replace: transforming string dates format

Question

I have big array fetched with diff strpos() and substr() :

$array[n] = ('Jan 23', 'From Jan 4 to Feb 1', 'Jul 5 to 10');

and I wish a process to convert it to:

$array[n] = ('2013-01-23','2013-01-04/2013-02-01','2013-07-05/2013-07-10);

Thanks for your help. I plan to use strpos() to get the date string into the array. after that, I plan to explode the date array, then perform a foreach($date as $index => $value), if I can cast it to string then it´s a date, and I could use two digits, for months match with monthly names. and then form the desired string.

Is there a better solution?

I think preg_replace is most inefficient way to do this. I think you should look for better method. — Kamil
– Kamil, Commented Jan 21, 2013 at 17:31
Have you considered what happends when a start date will be 25 December, and end date 1 January? There is no year given... — Kamil
– Kamil, Commented Jan 21, 2013 at 17:43

Tommaso Belluzzo · Accepted Answer · 2013-01-21 17:47:37Z

2

Why don't you use instead strtotime() function and date_format() function? It can be very difficult to handle all the possible formats with regular expressions and string parsing.

date('Y-m-d', strtotime('your_string'));

edited Jan 21, 2013 at 17:47

answered Jan 21, 2013 at 17:34

Tommaso Belluzzo

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1 Comment

nickb Over a year ago

Without any example code, this is more suited as a comment, and not an answer, especially as it is worded as a question.

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