preg replacing a string in PHP

Question

I'm currently writing a code obfuscator for PHP in PHP, just to improve my skills with regex syntax.

The goal is to base64_encode strings before any obfuscating processes, and decode it after any obfuscating processes. On standard strings like "foo bar" or 'foo bar' everything works, but it does not work with string containing escaped (double/simple) quotes like this one : 'return \'"\'.base64_encode($matches[0]).\'"\';'

As you can see, I'm trying to obfuscate my own code, which seems to be fun. But my own code contains specific regex strings, which aren't correctly parsed.

Here is the code in charge of encoding a string starting and ending with simple quotes (the code in charge to do the same thing with double quote is almost the same) :

    $this->output = preg_replace_callback('/(?<!\\\\)\'(.*)(?<!\\\\)\'/isU', create_function(
            '$matches',
            'return "\'".base64_encode($matches[0])."\'";'
        ), $this->output
    );

Any ideas ?

Why are you not obfuscating the whole string? Btw the i flag in your pattern is useless because there's nothing in the pattern that has a different representation in the "other" case. — inhan
– inhan, Commented Jan 24, 2013 at 0:54

fsw · Accepted Answer · 2013-01-24 00:03:15Z

1

please minimize your problem (post not working piece of code that is as simple as possible).

$test = "bla blah 'match \' this' blah blah";
$test = preg_match('/(?<!\\\\)\'(.*)(?<!\\\\)\'/isU', $test, $matches);
var_dump($matches);

works as charm.

answered Jan 24, 2013 at 0:03

fsw

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1 Comment

Alex Ception Over a year ago

I minimized my problem as much as I could.I tried your code (thanks by the way for your answer), but it doesn't work with a double quote in the middle of the string. That's pretty much what I would like to do, encoding a string regardless of the type of the delimiter, and regardless of the content.

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