Errors with using a timestamp in PHP

Question

I am receiving the error: A non well formed numeric value encountered

Here is my code:

<?php

$timestamp= '2013-01-20 18:20:20';

$datetime= date('F j, Y', $timestamp);

    echo $datetime;

?>

This returns January 1, 1970 Which isn't right. What am I doing wrong? BTW: All of my $timestamp variables will be in that format. I am using datetime in my MySQL database table.

Thanks

Just for clarification also, there are several "timestamps" (each database uses their own). php uses the "unix timestamp" which represents the number of seconds since "January 1, 1970 00:00:00 UTC". The timestamp the OP is using is not a valid "unix timestamp" and so date() thinks the "unix timestamp" passed in is 0 meaning 0 seconds since "Jan 1 1970". en.wikipedia.org/wiki/Unix_time — Jonathan Kuhn
– Jonathan Kuhn, Commented Jan 24, 2013 at 20:53

DiverseAndRemote.com · Accepted Answer · 2013-01-24 20:41:57Z

4

the date function takes a timestamp which is an int you need to call it using

date('F j, Y', time());

or

$timestamp= '2013-01-20 18:20:20';
date('F j, Y', strtotime($timestamp));

see http://php.net/manual/en/function.date.php for info on how to use the date function

answered Jan 24, 2013 at 20:41

DiverseAndRemote.com

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Comments

Arif · Accepted Answer · 2015-05-26 09:56:02Z

3

'2013-01-20 18:20:20' is not a timestamp . You have to convert it to timestamp. You can use strtotime function to do this.

$timestamp= strtotime('2013-01-20 18:20:20');

edited May 26, 2015 at 9:56

answered Jan 24, 2013 at 20:42

Arif

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