Join multiple selectors that are variables in jQuery

Question

Is it possible to join variables that are cashed selectors?

$('.active').each(function(){
  var $a = $(this);
  var $a_h5 = $a.closest('h5');
  var $a_h4 = $a.closest('h4');
});

Doesn't work:

$('[name=get]').html($($a_h4,$a_h5,$a).map(function() {
  return $(this).html();
}).get().join(', '));

Doesn't work:

$('[name=get]').html($a_h4.add($a_h5).add($a).map(function() {
  return $(this).html();
}).get().join(', '));

@elclanrs I'm trying to join content of h4 + content of h5 + content of .active and join all these results if there are more than one .active. — A. Z.
– A. Z., Commented Jan 25, 2013 at 8:19

Rab Khan · Accepted Answer · 2013-01-25 08:14:49Z

1

you could use

$('[name=get]').html($($.merge($a_h4,$a_h5,$a)).map(function() {

answered Jan 25, 2013 at 8:14

Rab Khan

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