Continue even in case of the error in javascript

Question

There are 2 scripts on the page. If the first one causes an error, then the second refuse to work because of this.

How do I make the second script turn a blind eye to the first one's errors and work anyway? Keep in mind that I'm not allowed to change the first script.

Show your problematic code and errors. Separate scripts shouldn't have any problems with each other unless second tries to use data that were supposed to be initialized in first. — Oleg V. Volkov
– Oleg V. Volkov, Commented Jan 25, 2013 at 11:20

anon · Accepted Answer · 2013-01-25 11:27:01Z

4

Maybe this might help

<script type="text/javascript">
    function stoperror()
    {
        return true;
    }
    window.onerror=stoperror();
</script>

MOZILLA DEVELOPER NETWORK window.onerror

answered Jan 25, 2013 at 11:27

anon

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Comments

AdityaParab · Accepted Answer · 2013-01-25 11:21:22Z

2

Javascript execution stops when the error occurs...

You can not change this behavior...

To get around, put the code that causes an error inside try block

try{
    //code that might produce some error
} catch(e){
}

answered Jan 25, 2013 at 11:21

AdityaParab

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Comments

Yoni Hassin · Accepted Answer · 2013-01-25 11:22:26Z

2

I would use try and catch blocks, and disregard any error.

That should work..

Example

try
{
    //Run some code here
}
catch(err)
{
    //Handle errors here
}

edited Jan 25, 2013 at 11:22

user1873471

answered Jan 25, 2013 at 11:20

Yoni Hassin

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3 Comments

AdityaParab Over a year ago

Right! (+1)... If there is an error and exception is not thrown, that would mean you have syntax error

marekful Over a year ago

Not necessarily syntax error. Any error that is not a thrown exception will still be an error. E.g. somevar.somefunc() if somevar is undefined, null, etc.. catch will only be entered if throw was issued during execution.

AdityaParab Over a year ago

in any case, whether your catch block gets fired or not, try will avoid script from crashing

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