Checking if array is multidimensional or not?

Use count() twice; one time in default mode and one time in recursive mode. If the values match, the array is not multidimensional, as a multidimensional array would have a higher recursive count.

if (count($array) == count($array, COUNT_RECURSIVE)) 
{
  echo 'array is not multidimensional';
}
else
{
  echo 'array is multidimensional';
}

This option second value mode was added in PHP 4.2.0. From the PHP Docs:

If the optional mode parameter is set to COUNT_RECURSIVE (or 1), count() will recursively count the array. This is particularly useful for counting all the elements of a multidimensional array. count() does not detect infinite recursion.

However this method does not detect array(array()).

For PHP 4.2.0 or newer:

function is_multi($array) {
    return (count($array) != count($array, 1));
}

After PHP 7 you could simply do:

public function is_multi(array $array):bool
{
    return is_array($array[array_key_first($array)]);
}

You could look check is_array() on the first element, under the assumption that if the first element of an array is an array, then the rest of them are too.

I think you will find that this function is the simplest, most efficient, and fastest way.

function isMultiArray($a){
    foreach($a as $v) if(is_array($v)) return TRUE;
    return FALSE;
}

You can test it like this:

$a = array(1 => 'a',2 => 'b',3 => array(1,2,3));
$b = array(1 => 'a',2 => 'b');

echo isMultiArray($a) ? 'is multi':'is not multi';
echo '<br />';
echo isMultiArray($b) ? 'is multi':'is not multi';

Don't use COUNT_RECURSIVE

click this site for know why

use rsort and then use isset

function is_multi_array( $arr ) {
rsort( $arr );
return isset( $arr[0] ) && is_array( $arr[0] );
}
//Usage
var_dump( is_multi_array( $some_array ) );

Even this works

is_array(current($array));

If false its a single dimension array if true its a multi dimension array.

current will give you the first element of your array and check if the first element is an array or not by is_array function.

You can also do a simple check like this:

$array = array('yo'=>'dream', 'mydear'=> array('anotherYo'=>'dream'));
$array1 = array('yo'=>'dream', 'mydear'=> 'not_array');

function is_multi_dimensional($array){
    $flag = 0;
    while(list($k,$value)=each($array)){
        if(is_array($value))
            $flag = 1;
    }
    return $flag;
}
echo is_multi_dimensional($array); // returns 1
echo is_multi_dimensional($array1); // returns 0

This function will return int number of array dimensions (stolen from here).

function countdim($array)
{
   if (is_array(reset($array))) 
     $return = countdim(reset($array)) + 1;
   else
     $return = 1;
 
   return $return;
}

I think this one is classy (props to another user I don't know his username):

static public function isMulti($array)
{
    $result = array_unique(array_map("gettype",$array));

    return count($result) == 1 && array_shift($result) == "array";
}

In my case. I stuck in vary strange condition.
1st case = array("data"=> "name");
2nd case = array("data"=> array("name"=>"username","fname"=>"fname"));
But if data has array instead of value then sizeof() or count() function not work for this condition. Then i create custom function to check.
If first index of array have value then it return "only value"
But if index have array instead of value then it return "has array"
I use this way

 function is_multi($a) {
        foreach ($a as $v) {
          if (is_array($v)) 
          {
            return "has array";
            break;
          }
          break;
        }
        return 'only value';
    }

Special thanks to Vinko Vrsalovic

Its as simple as

$isMulti = !empty(array_filter($array, function($e) {
                    return is_array($e);
                }));

$is_multi_array = array_reduce(array_keys($arr), function ($carry, $key) use ($arr) { return $carry && is_array($arr[$key]); }, true);

Here is a nice one liner. It iterates over every key to check if the value at that key is an array. This will ensure true