class MyClass:
def myMethod(self):
pass
myInstance = MyClass()
methodReference = myInstance.myMethod
Now can you get a reference to myInstance if you now only have access to methodReference?
3 Answers
Try this:
methodReference.im_self
If you are using Python 3:
methodReference.__self__
1 Comment
Dmytro Bugayev
old question, but this should now be the accepted answer as it's the only one to provide a solution for python3
If you are using Python 3:
methodReference.__self__
Otherwise:
methodReference.im_self
and by a similar token, for the class:
methodReference.im_class
For this kind of code discovery you should install iPython and use tab, for instance, in your case myReference.+TAB would give:
In [6]: methodReference. methodReference.im_class
methodReference.im_func methodReference.im_self
Hence, you don't need to worry about remembering things so much - you know that the method is probably provided by the function object and from the suggestions that iPython gives it's usually obvious what method/attribute you're looking for.
2 Comments
Evgeny Zislis
This doesn't work in Python 3. See @dusan answer.
Mike Vella
@Evgeny thanks - this answer was from 2013, I updated my answer.
You can work this out yourself - have a look at the dir output:
>>> dir(mr)
['__call__', ... '__str__', '__subclasshook__', 'im_class', 'im_func', 'im_self']
The im_* instances refer to attributes defined for instance methods...
The class it was defined in, the function code block, and the object it is bound to...
1 Comment
Mike Vella
The reason I slightly prefer the iPython approach I detail above is that it hides special methods/attributes and formats on the screen slightly cleaner. But of course they're pretty equivalent in terms of functionality and your suggestion doesn't tie the user down to iPython either.
methodReference.im_self(dir()is your friend)