regex for phone number validation?

Question

i want to validate my phone number with the regex for following formats.i have googled the things but i could not find the regex for following formats...

    079-26408300 / 8200
    (079) 26408300
    079 264 083 00 
    9429527462

can anyone please guide me how can i do validate the phone number field for above formats? I want to validate the phone number for only above formats as right now am using only following regex var phone_pattern = /^[a-z0-9]+$/i;

@Ali Shah Ahmed

var phone_pattern = "(\d{10})|(\d{3}-\d{8}\s/\s\d{4})|((\d{3}\s){3}\d{2})|((\d{3})\s\d{8})";

here is the way am checking if its valid

if (!phone_pattern.test(personal_phone))
        {
            $("#restErrorpersonalphone").html('Please enter valid phone number');
            $("#personal_phone").addClass('borderColor');
            flag = false;
        } else {
            $("#restErrorpersonalphone").html('');
            $("#personal_phone").removeClass('borderColor');
        }

its not working. Am I implementing in wrong way?

Wouldn't it be better to just strip away everything but numbers and deal with the raw numbers, no spaces, parentheses, pluses, etc? — Ryan Amos
– Ryan Amos, Commented Jan 30, 2013 at 4:55
ok..let say i dont want parenthesis +.but its required to use - ..please see my updated question — BhavikKama
– BhavikKama, Commented Jan 30, 2013 at 4:59
Have you search SO for this before posting? There are many post about validating a phone number. — nhahtdh
– nhahtdh, Commented Jan 30, 2013 at 5:24

Ali Shah Ahmed · Accepted Answer · 2013-01-30 06:24:26Z

1

lets start with the simplest phone number 9429527462
As this has 10 characters and all are numbers, regex for it could be \d{10}

Now the next phone number 079 264 083 00. Regex for this pattern could be (\d{3}\s){3}\d{2} First we are expecting a group of 3 digits and a space to repeat thrice (\d{3}\s){3}, this will cover 079 264 083 (space included in it), so left will be the last two characters which are handled using \d{2}

For the phone number (079) 26408300, $\d{3}$\s\d{8} regex could be use. The regex first looks for a opening bracket, then three digits inside it, and then the closing bracket. It then looks for a space, and then for 8 digits.

The phone number 079-26408300 / 8200 could be validated using regex \d{3}-\d{8}\s/\s\d{4}. It first looks for 3 digits then a -, then 8 digits followed by a space. Then looks for a / and then a space and then 4 digits.

If you wish to know a single regex for validating all the above patterns, do let me know.

Final combined regex would be:

/(\d{10})|(\d{3}-\d{8}\s\/\s\d{4})|((\d{3}\s){3}\d{2})|(\(\d{3}\)\s\d{8})/

edited Jan 30, 2013 at 6:24

answered Jan 30, 2013 at 5:14

Ali Shah Ahmed

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8 Comments

BhavikKama Over a year ago

yes ..if u can provide me single regex then it will be useful..thanks for this wonderful answer with details

Ali Shah Ahmed Over a year ago

well i would keep it as simple as possible. "(\d{10})|(\d{3}-\d{8}\s/\s\d{4})|((\d{3}\s){3}\d{2})|((\d{3})\s\d{8})" (Please note there is no need of quotation marks, i put these just to seperate the regex from rest of the comment) I believe this regex would do the work. What i did is just combined all the mentioned regex with OR statements. So it would match all the mentioned patterns.

BhavikKama Over a year ago

can u please see my updated question am quite new in this regex so..please help me as i dont know how i put this in my javascript

Ali Shah Ahmed Over a year ago

there are some small mistakes. Firstly do not put your regex in inverted commas. var phone_pattern = /(\d{10})|(\d{3}-\d{8}\s/\s\d{4})|((\d{3}\s){3}\d{2})|((\d{3})\s\d{8})/ start and end your regex with a forward slash. Secondly, the regex contains a forward slash in itself, try replacing that forward slash with a backslash and a forward slash, "\/" So finally the code will look like: var phone_pattern = /(\d{10})|(\d{3}-\d{8}\s\/\s\d{4})|((\d{3}\s){3}\d{2})|((\d{3})\s\d{8})/

Ali Shah Ahmed Over a year ago

hey i just noticed that two of the backslashes are removed in the comment, so i updated my answer with the final regex. Try following the steps mentioned in my previous comment, and replace the final regex with the one mentioned in my answer.

|

Evgeniy Dorofeev · Accepted Answer · 2013-01-30 05:38:03Z

0

Straightforward solution is simple, use |

String ex = "\\d{3}-\\d{8} / \\d{4}|\\(\\d{3}\\) \\d{8}|...

edited Jan 30, 2013 at 5:38

answered Jan 30, 2013 at 5:00

Evgeniy Dorofeev

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