Open specific app based on URL

Question

I will like to open an app if the url

for example if the person opens : http://www.example.com/id=100, i would like to parse example.com and show options to open it with my app.

The same functionality is used by youtube, if you click on youtube link it will either ask if you would like to open it using youtube or directly play youtube video

Use an intent. The answer by Nirav should work for you.

Raghunandan
– Raghunandan

2013-01-30 05:40:05 +00:00
Commented Jan 30, 2013 at 5:40 — Raghunandan
– Raghunandan, Commented Jan 30, 2013 at 5:40

rekire · Accepted Answer · 2013-01-30 05:51:57Z

7

You can add a data specification to your intent filter with the http schema and the domain you want to open with your app.

<intent-filter ... >
    <data android:scheme="http" android:host="example.com" />
    ...
</intent-filter>

edited Jan 30, 2013 at 5:51

answered Jan 30, 2013 at 5:32

rekire

48.1k34 gold badges184 silver badges279 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Franci Penov Over a year ago

Umh, that line up there is the snippet from the manifest file.

Nirav Ranpara · Accepted Answer · 2013-01-30 05:34:05Z

1

Intent LaunchIntent = getPackageManager().getLaunchIntentForPackage("com.package.address");
startActivity(LaunchIntent);

answered Jan 30, 2013 at 5:34

Nirav Ranpara

13.8k4 gold badges43 silver badges56 bronze badges

Collectives™ on Stack Overflow

Open specific app based on URL

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related