Sending data with AJAX to a PHP file and using that data to run a PHP script

Question

I'm currently trying to make live form validation with PHP and AJAX. So basically - I need to send the value of a field through AJAX to a PHP script(I can do that) and then I need to run a function inside that PHP file with the data I sent. How can I do that?

JQuery:

$.ajax({
  type: 'POST',
  url: 'validate.php',
  data: 'user=' + t.value,   //(t.value = this.value),
  cache: false,
  success: function(data) {
    someId.html(data);
  }
});

Validate.php:

// Now I need to use the "user" value I sent in this function, how can I do this?

function check_user($user) {
  //process the data
}

If I don't use functions and just raw php in validate.php the data gets sent and the code inside it executed and everything works as I like, but if I add every feature I want things get very messy so I prefer using separate functions.

I removed a lot of code that was not relevant to make it short.

you can get data in $_POST and than call that function whats problem ? — NullPoiиteя
– NullPoiиteя, Commented Feb 4, 2013 at 14:38
You could pass in a post data value of 'function=check_user' and then in the php code use a switchcase command pattern to execute accordingly, see stackoverflow.com/questions/2269307/… for more deats... — Opentuned
– Opentuned, Commented Feb 4, 2013 at 14:40

Yevgen · Accepted Answer · 2013-02-04 14:41:16Z

2

1) This doesn't look nice

data: 'user=' + t.value,   //(t.value = this.value),

This is nice

data: {user: t.value},

2) Use $_POST

function check_user($user) {
    //process the data
}
check_user($_POST['user'])

answered Feb 4, 2013 at 14:41

Yevgen

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2 Comments

ejx Over a year ago

Yes, I read that previously today, but why exactly is the {user: t.value} better?

Yevgen Over a year ago

It is easier to read and it is syntax of official documentation. So I suppose you better hold to this syntax if you don't want to get in trouble now and later.

Christoph Grimmer · Accepted Answer · 2013-02-04 14:39:44Z

1

You just have to call the function inside your file.

if(isset($_REQUEST['user'])){
    check_user($_REQUEST['user']);
}

answered Feb 4, 2013 at 14:39

Christoph Grimmer

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2 Comments

ejx Over a year ago

Thanks! This is what I was looking for. With some more tinkering I managed to get things working by calling the function at the top of my PHP, but this is much better!

Christoph Grimmer Over a year ago

I did not include this in my answer - but please take care to sanitize ANY input you receive via GET, POST etc.! If you don't this will open doors wide for XSS and SQL injection.

mileusna · Accepted Answer · 2013-02-04 14:47:14Z

1

In your validate.php you will receive classic POST request. You can easily call the function depending on which variable you are testing, like this:

<?php

if (isset($_POST['user'])) {
    $result = check_user($_POST['user']);
}
elseif (isset($_POST['email'])) {
    $result = check_email($_POST['email']);
}
elseif (...) {
    // ...
}

// returning validation result as JSON
echo json_encode(array("result" => $result));
exit();

function check_user($user) {
   //process the data
   return true; // or flase
}

function check_email($email) {
   //process the data
   return true; // or false
}

// ...
?>

answered Feb 4, 2013 at 14:47

mileusna

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Comments

Michal Trojanowski · Accepted Answer · 2013-02-04 14:40:50Z

0

The data is send in the $_POST global variable. You can access it when calling the check_user function:

check_user($_POST['user']);

If you do this however remember to check the field value, whether no mallicious content has been sent inside it.

answered Feb 4, 2013 at 14:40

Michal Trojanowski

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Comments

Dave · Accepted Answer · 2013-02-04 14:42:02Z

Here's how I do it

Jquery Request

$.ajax({
            type: 'POST',
            url: "ajax/transferstation-lookup.php",
            data: {
                'supplier': $("select#usedsupplier").val(),
                'csl': $("#csl").val()
            },
            success: function(data){
                if (data["queryresult"]==true) {
                    //add returned html to page
                    $("#destinationtd").html(data["returnedhtml"]);
                } else {
                    jAlert('No waste destinations found for this supplier please select a different supplier', 'NO WASTE DESTINATIONS FOR SUPPLIER', function(result){ return false; });
                }
            },
            dataType: 'json'
        });

PHP Page Just takes the 2 input

$supplier = mysqli_real_escape_string($db->mysqli,$_POST["supplier"]);
$clientservicelevel = mysqli_real_escape_string($db->mysqli,$_POST["csl"]);

Runs them through a query. Now in my case I just return raw html stored inside a json array with a check flag saying query has been successful or failed like this

$messages = array("queryresult"=>true,"returnedhtml"=>$html);
echo json_encode($messages); //encode and send message back to javascript

If you look back at my initial javascript you'll see I have conditionals on queryresult and then just spit out the raw html back into a div you can do whatever you need with it though.

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