how to gettext in edittext to array

Question

How can I get the value of EditText then store it in my array?

This is my full code:

EditText op = (EditText)v.findViewById(R.id.operator);
array=new int [Integer.valueOf(op.getText().toString())];

for (i = 0;i<(array.length+1);i++){
    LayoutInflater inflater = MainActivity.this.getLayoutInflater();
    final View v2=inflater.inflate(R.layout.inputangka, null) ;
    new AlertDialog.Builder(MainActivity.this)
        .setIcon(R.drawable.ic_launcher)
        .setTitle("number of-"+(i-1)+":")
        .setView(v2)
        .setNeutralButton("Ok", new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dlg, int sumthin) {
                EditText number = (EditText)v2.findViewById(R.id.number);
                int number1 = Integer.valueOf(number.getText().toString());
                array [i]= number1; //error line

My error log:

02-05 16:33:31.374: E/AndroidRuntime(431): java.lang.ArrayIndexOutOfBoundsException

How do I solve this?

for (i = 0;i<(array.length+1);i++) - Seems like that's your problem. The +1 puts you beyond the last index in the array. — eldarerathis
– eldarerathis, Commented Feb 5, 2013 at 17:05
i have remove +1 and i am compile again but my error same,,,,on array [i]= number1; — Ash
– Ash, Commented Feb 5, 2013 at 17:09

Ajay S · Accepted Answer · 2013-02-05 17:12:58Z

1

This occur because for ex you enter 5 in edit text. Now you are iterate the loop until less than 6 from initial value 0.

When counter reach to 5 then your condition will become true 5 < 6 then but there array size is 5 here you are accessing the 6th element. So it throwing the ArrayIindexOutOfBound Exception.

To get rid from this problem.

Try this.

for (i = 0; i<(array.length);i++){
    //Code
}

edited Feb 5, 2013 at 17:12

answered Feb 5, 2013 at 17:06

Ajay S

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6 Comments

Cat Over a year ago

The second one will not actually cause an exception. It would just set the title to "number of--1:", "number of-0:", and so on.

Ash Over a year ago

i have removed then my problem is same,,,,,

Ajay S Over a year ago

@user1759316 Same error then post the logcat i can not imagine

Ash Over a year ago

FATAL EXCEPTION: main java.lang.ArrayIndexOutOfBoundsException at com.example.dialog_looping.MainActivity$1$1.onClick(MainActivity.java:48) at com.android.internal.app.AlertController$ButtonHandler.handleMessage(AlertController.java:159) at android.os.Handler.dispatchMessage(Handler.java:99) at android.os.Looper.loop(Looper.java:123) at android.app.ActivityThread.main(ActivityThread.java:3683) at java.lang.reflect.Method.invokeNative(Native Method) at java.lang.reflect.Method.invoke(Method.java:507)

Ajay S Over a year ago

@user1759316 What is written on MainActivity.java:48 and have you made change in java file what i have told above and make sure you have compiled the java class.

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AAnkit · Accepted Answer · 2013-02-05 17:15:07Z

0

remove +1 from for (i = 0;i<(array.length+1);i++){ and it will work like a charm.

answered Feb 5, 2013 at 17:15

AAnkit

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6 Comments

Ash Over a year ago

same error, this is my error logcat and my full code docs.google.com/document/d/…

Ash Over a year ago

yeah, sorry i am newbie, please give me code for looping dialog,,,

AAnkit Over a year ago

I will give it, But what is the logic, I mean what you are trying to do?

Ash Over a year ago

i want to create dialog loop, if i am input 3 then dialog looping 3x, and my value on dialog loop store in array then show. if on dialog looping 1st iam input 10 then dialog show 10, 2nd dialog i am input 20 then dialog show 10+20,i am input 3rd 30 then dialog show 10+20+30 and etc depending on the input number of looping dialog

Ash Over a year ago

please wait i am upload my design

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coading fever · Accepted Answer · 2013-02-05 17:28:24Z

0

you just need to replace the for condition by following code.

for (i = 0;i<(array.length-1);i++){

It will work for sure.

answered Feb 5, 2013 at 17:28

coading fever

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Comments

AbdulHannan · Accepted Answer · 2013-02-05 17:48:24Z

0

See, your onClick() is getting executed after your loop is finished executing and hence the value of i is one more than the array last index. For a workaround, save that value into another temporary integer variable and then send it. It will surely work then.

answered Feb 5, 2013 at 17:48

AbdulHannan

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