I am having a slight problem in Regular expressions, I would like to check if my string is in the range of 2008-13. This is were I won't to place the Regex
Array[k].startsWith("")
I have tried so far:
(200+[8-9])|(201+[0-9])
and
^20+[0-1][0-9]$
but the second one I think it will give me 2000-2019.
I would appreciate any help.
Try below logic..
public class Lottery{
// Do not change main().
public static void main(String [] args) throws Exception{
String[] myArray ={"2008","2009"};
for (String val : myArray) {
int year = Integer.parseInt(val);
if(year<=2013 && year>=2008)
{
// To do
}
}
}
}
The regex would be:
^200[89]|201[0-3]$
but, unless you're being forced to use a single regex for validation, I'd simply parse it as an integer then check the range with an if statement.
You don't want those + characters in there since they mean one or more of the preceding objects. Hence 20+[89] would allow 200000000000000009.
Your mistake is in using +. Fix your regex as following:
(200[8-9])|(201[0-9])
But better extract the year, parse it and verify as integer:
Pattern p = Pattern.compile("(\\d{4})");
Matcher m = p.matcher(str);
if (m.find()) {
int year = Integer.parseInt(m.group(1));
if (year > 2008 && year < 2019) {
// do something
}
}
This is much more robust for future modification: the year top and bottom values can be read from file, DB etc in future.
Your best shot for similar tasks would be to parse the String as Integer and compare the integers otherwise any approach you offer will be error-prone.
Still one solution that will work is:
(2008|2009|2010|2011|2012|2013)
No weird edge cases, easy to understand.
This is a simple regexpr (probably not the best):
20(08|09|10|11|12|13)
Array[k]returns aStringthen,String.startsWith()doesn't accept regex as a param .