how to insert string to given string in oracle?

Question

i am having one string test1string i need to pad three zeros before every digit.the result string should be test0001string.I have tried PAD,regexp_instr but i didn't get the correct result.can anybody explain me
thanks in advance

Vincent Malgrat · Accepted Answer · 2013-02-15 12:29:00Z

4

You can use REGEXP_REPLACE:

SQL> SELECT regexp_replace('test1string', '([[:digit:]])', '000\1') tx FROM dual;

TX
--------------
test0001string

answered Feb 15, 2013 at 12:29

Vincent Malgrat

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