Find values in multidimensional array

Question

Assume I have an array in my script and it's made up like this:

   var detail= {};
   detail['i100']=new Array()

   detail['i100']['ID 4564']= 'John'  
   detail['i100']['ID 4899']= 'Paul' 
   detail['i100']['ID 9877']= 'Andy'
   detail['i100']['ID 1233']= 'Evan'

   detail['i25'] = new Array()  

   detail['i25']['ID 89866']= 'Paul s'  
   detail['i25']['ID 87866']= 'Paul'

I then use this script to get the values of the first part of the array:

   $.each(detail, function(vehicle) {
    console.log( vehicle ) 
   });

This gives me two results as expected (i100 and i25), What I want to do however is, by using the reference vehicle, get all the names and values of the second dimension – i.e. by using i25 I want to return ID 89866 and ID 87866. I have tried children(), but it is just not working. Does anyone have any advice, please ?

possible duplicate of I have a nested data structure / JSON, how can I access a specific value? — Felix Kling
– Felix Kling, Commented Feb 18, 2013 at 20:54
Btw, you really should not use arrays with anything else than numerical keys. detail['i100']=new Array() should be detail['i100'] = {}, i.e. it should be an object. — Felix Kling
– Felix Kling, Commented Feb 18, 2013 at 20:54
children() is for a jQuery set NOT for an array. Use the normal Array methods and accessors to get at array elements. — prodigitalson
– prodigitalson, Commented Feb 18, 2013 at 20:56
@adeneo: Well, arrays are objects, but they have special methods that only work on properties with numerical property names. The code is totally valid, but e.g. detail['i25'].length would return 0. — Felix Kling
– Felix Kling, Commented Feb 18, 2013 at 20:56
@adeneo: As I said, arrays are objects. Always. But that typeof arr returns 'object' is rather a shortcoming of the language. — Felix Kling
– Felix Kling, Commented Feb 18, 2013 at 20:58

Joel Grannas · Accepted Answer · 2013-02-18 21:06:12Z

2

You need to run another each on the 2nd dimension.

$.each(detail, function(index,value){
    $.each(value, function(i,v) {
        console.log(v);
    });
});

or if you want to specifically call one item, pass in the value name:

function getByName(name){
    $.each(detail[name], function(i,v){
        console.log(v);
    });
}

edited Feb 18, 2013 at 21:06

answered Feb 18, 2013 at 20:57

Joel Grannas

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3 Comments

Mick Over a year ago

I tried that but I get this error Uncaught TypeError: Cannot use 'in' operator to search for '3' in i100

Joel Grannas Over a year ago

try it now with my edits... i forgot each callback function uses (index,value)

Joel Grannas Over a year ago

No prob! Glad you got it. The best way to show your appreciation is to upvote and accept my answer :)

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