PHP code to get the json output in the following format

Question

Hi i have written an android app which interacts with php to get data from the database.

I need the json to return the data back in this format.

[
    {
        "outlet_id"    :"1",
        "outlet_desc"  :"BigBazaar",
        "outlet_loc"   :"Jayanagar4thBlock",
        "outlet_image" :"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FBigBazaar.png",
        "recommended_products": [
                                    {
                                        "item_id":"3",
                                        "item_desc":"Dettol",
                                        "item_image":"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FDettol.png"
                                    }
                                ]
    },
    {
        "outlet_id":"2",
        "outlet_desc":"FoodWorld",
        "outlet_loc":"Basavanagudi",
        "outlet_image":"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FFoodWorld.png","
        recommended_products":[
                                {
                                    "item_id":"3",
                                    "item_desc":"Dettol",
                                    "item_image":"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FDettol.png"
                                },
                                {
                                    "item_id":"3",
                                    "item_desc":"Colgate",
                                    "item_image":"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FColgate.png"
                                }
                              ]
    },
    {
        "outlet_id":"5",
        "outlet_desc":"Total",
        "outlet_loc":"MurgeshPalaya",
        "outlet_image":"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FTotal.png",
        "recommended_products":[
                                {
                                    "item_id":"3",
                                    "item_desc":"Dettol",
                                    "item_image":"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FDettol.png"


                                },
                                {
                                    "item_id":"3",
                                    "item_desc":"Colgate",
                                    "item_image":"http%3A%2F%2Flocalhost%2FFlutura%2FPHP%2FAssets%2Fimages%2FColgate.png"

                                }
                               ]
     }
]

But right now it is giving in the following format.

[
    [
        {
            "outlet_id": "1",
            "outlet_name": "Big Bazaar",
            "lat": "12.9285690",
            "lng": "77.5831100",
            "outlet_image": "images/BigBazaar.png",
            "outlet_location": "Jayanagar 4th Block"
        }
    ],
    [
        {
            "outlet_id": "2",
            "outlet_name": "Food World",
            "lat": "12.9392350",
            "lng": "77.5780680",
            "outlet_image": "images/FoodWorld.png",
            "outlet_location": "Basavanagudi"
        }
    ],
    [
        {
            "outlet_id": "5",
            "outlet_name": "Total",
            "lat": "12.9589340",
            "lng": "77.6571610",
            "outlet_image": "images/Total.png",
            "outlet_location": "Murugeshpalya"
        }
    ],
    [
        {
            "outlet_id": "6",
            "outlet_name": "Big Bazaar",
            "lat": "12.9324963",
            "lng": "77.6228463",
            "outlet_image": "images/BigBazaar.png",
            "outlet_location": "Koramangala"
        }
    ],
    [
        {
            "outlet_id": "7",
            "outlet_name": "Food World",
            "lat": "12.9785055",
            "lng": "77.6379353",
            "outlet_image": "images/FoodWorld.png",
            "outlet_location": "Indira Nagar"
        }
    ]
]

This is my php code.

<?php
error_reporting(0);

//$url = $_GET['url'];
//$mR = $_GET['mRequest'];
//$mOid = $_GET['mOutletId'];
//$mloc = $_GET['mLocation'];
//connect to the db
$user = "root";
$pswd = "";
$db = "recommendations_db";
$host = "localhost";
$conn = mysql_connect($host, $user, $pswd);
mysql_select_db($db);
//if($mR == 'outlets' && $mloc = 'all'){
$query = "SELECT * FROM outlets";
$result = mysql_query($query) or die("Unable to verify user because : " . mysql_error());

while($row = mysql_fetch_assoc($result))
{
  $output[] = array($row); 
}
print( json_encode($output) );
?>

How can i modify the above php code to return in the 1st format. Please help as i am not so good in php.

Table Structure.

Outlets Table.

It contains the following fields.

outlet_id outlet_name lat lng outlet_image outlet_location

Recommendations table.

It contains the following fields.

item_id outlet_id

Items table.

It contains the following fields.

item_id item_name item_image item_price category_id

Popnoodles · Accepted Answer · 2013-02-21 02:53:01Z

1

Ok so it's the missing sub-array. You want to create a JSON string, not a object, from a multidimensional associative array.

There are faster ways to select these rows but this is easy to follow.

$query = "SELECT * FROM outlets";
$result = mysql_query($query) or die("Unable to verify user because : " . mysql_error());

$output=array(); # don't leave it undefined
while($row = mysql_fetch_assoc($result))
{
    # guessing this query
    $query2 = "SELECT * FROM recommended_products WHERE outlet_id=".$result['outlet_id'];

    # now we create the sub array recommended_products
    $row['recommended_products']=array();
    $result2 = mysql_query($query2) or die("Unable to verify user because : " . mysql_error());
    while($row2 = mysql_fetch_assoc($result2)){
        $row['recommended_products'][]=$row2;
    }

    # then add the modified row to the output
    $output[] = $row; 
}
print( json_encode($output) );

Also, mysql_ is depreciated. Probably no genuine need to rush but it's worth at least looking at converting to mysqli or PDO.

edited Feb 21, 2013 at 2:53

answered Feb 21, 2013 at 2:47

Popnoodles

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1 Comment

user1881440 Over a year ago

Hi i have added the table structure can you tell me now how to join the following tables to get the above format? @popnoodles

KaeruCT · Accepted Answer · 2013-02-21 02:30:47Z

0

Change $output[] = array($row); to $output[] = $row;

answered Feb 21, 2013 at 2:30

KaeruCT

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4 Comments

user1881440 Over a year ago

i get it in the same format if i do that and i guess i havent shown my db structure

Popnoodles Over a year ago

this solution looks right to me, unless by getting the same format you're referring to recommended_products being missing.

user1881440 Over a year ago

yes sry i think thats the problem this not being my code its already pissed me off and dunno y i didnt see that.

user1881440 Over a year ago

Could you give me some examples on how to get the output in the above format ie; embed one json object in another.

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