Python function returning many arguments

Question

I know, it's a noob question..

I have these variables:

pgwdth = 30;  
mrgn = 0;  
fmt = True

And this function:

def Param(x,pgwdth,mrgn,fmt):
    parametros = x.split(" ")
    if parametros[0][1] == "p":
    numerozinho = int(parametros[1])
        print "Changing pgwdth"
        pgwdth += numerozinho
        print pgwdth
    elif parametros[0][1] == "m":
        numerozinho = int(parametros[1])
        print "Changing mrgn"
        mrgn += numerozinho
        print mrgn
    elif parametros[0][1] == "f":
        numerozinho = parametros[1]
        print "On/Off"
        if numerozinho == "on\n":
            fmt = True
        elif numerozinho == "off\n":
            fmt = False
        else:
            "Error"
        print fmt
    else:
    print "Error"

I just want it to return the variables that it used as arguments after changing it.

return x,pgwdth,mrgn,fmt as the last statement.

eumiro
– eumiro

2013-02-27 11:05:59 +00:00
Commented Feb 27, 2013 at 11:05 — eumiro
– eumiro, Commented Feb 27, 2013 at 11:05

Gjordis · Accepted Answer · 2013-02-27 11:06:28Z

3

return x,pgwdth,mrgn,fmt

Simple as that.

And where you call it:

val1,val2,val3,val = Param(x,pgwdth,mrgn,fmt)

answered Feb 27, 2013 at 11:06

Gjordis

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John La Rooy · Accepted Answer · 2013-02-27 12:21:46Z

3

A function returns exactly one result. The trick is to make that result a tuple containing the multiple values.

return (x, pgwdth, mrgn, fmt)

In Python syntax the braces around the tuple are optional so you'll more often see

return x, pgwdth, mrgn, fmt

Which looks like returning multiple values, but now it's clear there is really just one return value

answered Feb 27, 2013 at 12:21

John La Rooy

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1 Comment

Gjordis Over a year ago

Little quirks like that make Python harder to read, but more interesting to code.

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