return json object fron function

Question

I am trying to return a json object from a function and use it as the below code, but it's not working. what wrong with it?

var x = [ "EditFileName" , "dosometing" ];
c_loadAjax.apply(this,x).done(function(json){
    alert(json.error);
});
function c_loadAjax( post , option ){
    $.ajax({
        type:"POST",
        url:"/includes/Ajax.php",
        data:{post:post,option:option},
        error:function(result){
            return '{"error":"Error"}';
        },
        success:function(result){
            return jQuery.parseJSON(result);
        }
    });
}

I think you have to return the deferred object itself to use it with .done — sofl
– sofl, Commented Feb 28, 2013 at 11:29

MathKimRobin · Accepted Answer · 2013-02-28 11:40:13Z

1

Try with the return keyword

var x = [ "EditFileName" , "dosometing" ];
c_loadAjax.apply(this,x).done(function(json){
    alert(json.error);
});
function c_loadAjax( post , option ){
    return $.ajax({
        type:"POST",
        url:"/includes/Ajax.php",
        data:{post:post,option:option},
        error:function(result){
            return '{"error":"Error"}';
        },
        success:function(result){
            return jQuery.parseJSON(result);
        }
    });
}

answered Feb 28, 2013 at 11:40

MathKimRobin

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2 Comments

kamal Over a year ago

it's actually returning data as json and works fine. but is it really okey to use it like this?

MathKimRobin Over a year ago

no, prefer ask for datatype:'json' in your request and give callbacks (success and fail functions) to your c_loadAjax as parameters

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