json first index value get in jquery

Question

I am generating JSON via an Ajax loop which I am successfully iterating and getting results. I need only the first index value of JSON which is name and I am doing this as in jQuery:

PHP

 $jsonRows[] = array(
            "name" => $result['name'],
            "datetime" => $result['datetime'],
            "place" => $result['place'],

        );
print_r(json_encode($jsonRows));

suppose the values are coming:

name: raj,
datetime: 2013-03-01 16:50:21,
place: India

name: jatin,
datetime: 2013-03-01 20:50:21,
place: US

name: raman,
datetime: 2013-03-03 01:50:21,
place: Japan

I need only name: raj but I am not getting this value:

JavaScript

$.each(response, function(i, item) {
       alert(item(0).name);
    });

error: object is not a function

is response an array? can you check the result for console.log(result) in the console. Add it before the $.each loop — Arun P Johny
– Arun P Johny, Commented Mar 4, 2013 at 14:01

bipen · Accepted Answer · 2013-03-04 14:03:53Z

4

try this

$.each(response, function(i, item) {
   alert(item.name);
});

example fiddle here

updated

if you need just the first one only thn no need of loop..

alert(response[0].name);

updated fiddle

edited Mar 4, 2013 at 14:03

answered Mar 4, 2013 at 13:54

bipen

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3 Comments

Naresh Over a year ago

each() is loop in j query and it will return all the index which have name key. I need only first name:raj

Naresh Over a year ago

ya your fiddle returning all the names.. but not only one.. which is raj

bipen Over a year ago

ok i got...try this..response[0].name.. if you need only one then no need of loop each..jsfiddle.net/bipen/L9Zfx/3

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