php - prepend an array value with key [duplicate]

Question

I have an array. It looks like this

$choices = array(
array('label' => 'test1','value' => 'test1'),
array('label' => 'test2','value' => 'test2'),
array('label' => 'test3','value' => 'test3'),
)

Now i would like to prepend this value in $choices array

array('label' => 'All','value' => 'all'),

It looks like I cannot use array_unshift function since my array has keys.

Can someone tell me how to prepend?

yes, it'll work just fine. even though you don't have explicitly defined keys in $choices, every HAS to have keys. — Marc B
– Marc B, Commented Mar 7, 2013 at 18:45
I don't see why you can't use array_unshift; every array has keys. — jeroen
– jeroen, Commented Mar 7, 2013 at 18:45
It looks like you can. The outer array is a list, with numeric keys. What you put inside (a distinct associative array) doesn't matter. — mario
– mario, Commented Mar 7, 2013 at 18:45

Mike Brant · Accepted Answer · 2013-03-07 18:47:29Z

2

Your $choices array has only numeric keys so array_unshift() would do exactly what you want.

$choices = array(
    array('label' => 'test1','value' => 'test1'),
    array('label' => 'test2','value' => 'test2'),
    array('label' => 'test3','value' => 'test3'),
);
echo $choices[0]['label']; // echoes 'test1'

$array_to_add = array('label' => 'All','value' => 'all');
array_unshift($choices, $array_to_add);

/* resulting array would look like this:
$choices = array(
    array('label' => 'All','value' => 'all')
    array('label' => 'test1','value' => 'test1'),
    array('label' => 'test2','value' => 'test2'),
    array('label' => 'test3','value' => 'test3'),
);
*/
echo $choices[0]['label']; // echoes 'All'

answered Mar 7, 2013 at 18:47

Mike Brant

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